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Rules:
0-9 Sudoku: Fill in the grid with digits, which can’t repeat in any row, column and marked 3x3 box. In each of these regions, one of the digits 1-9 has been replaced by a 0. No two rows, columns or boxes are missing the same digit.
2-whisper line: Two adjacent digits along the line must have a difference of at least 2.
Kropki dots: Digits separated by a small white dot are consecutive. Digits separated by a black dot are in a 2:1 ratio. Not all dots are necessarily given.
Strict quadkis: Large circles in the grid indicate that the cells touching them contain digits that are in a 2:1 ratio with the diagonally adjacent digit that touches the same circle. No other cells can be in a 2:1 ratio with any of their diagonally adjacent digits. In the cases where a digit is given inside a circle, it must appear in at least one of the cells that touch the circle.
In addition, digits inside a circle cannot be missing from the row, column and box that contain any of the four cells that touch that circle.
Many thanks to Bellsita and Myxo for testing (and for being so patient with my many mistakes) ❤️
Lösungscode: Row 9, read left to right (9 digits, no spaces)
am 21. Februar 2025, 17:23 Uhr von gfoot
Nice puzzle, the constraints worked really well I thought, and of course the initial setup with given digits and quads is aesthetically pleasing
You might want to check out kafkapharnaum's Doppelganger rules as your use of 0 is close to - but not the same as - his
am 21. Februar 2025, 08:00 Uhr von Gnoshia
Great puzzle! I think it is closer to 2 or 3 star difficulty
am 21. Februar 2025, 04:42 Uhr von rubencubed
splendid! and what a brain wrinkler! I spent the entire puzzle rehashing the logic in my brain, but never for a second was I at a loss of where to look and what to examine next.
my only critique is in the instructions: clarifying that the 0 may replace different numbers for the column vs the row vs the box (I assume you're getting at this with "In each of these regions"); and explicitly formulating that a ratio of a:b is equivalent x:y iff ay=bx.
all around loved the puzzle, though :D