Now, following right after that bonus puzzle...
Here's a project with an idea that has also been in my shimmering list of puzzle ideas for a long while, though it's more like an alternative route of that idea.
This is also my first step into the deconstruction concept and stations concept, at the end it rather acts like a proof of concept and it's built on a smaller size of the main thing with digits 1-9 (which I haven't tried so yet), but if this one gets enough appreciation then I may try to set the main thing at some point in the future.
For now, let's see how this goes:
Rules:
- Located within the grid are 7 orthogonally connected regions that contain digits 1-7 once each so that digits don't repeat in any row or column of the entire grid. Any two regions cannot touch orthogonally but may touch diagonally.
- The 'region number N' of a region is defined as digit N in the
top-left cell of that region, i.e.
the left most cell in the top most row (in this case, top most is prioritized over left most). Each digit from 1 to 7 must occupy a region number once.
- Draw a single loop, which goes orthogonally and doesn't branch or intersect itself, that must go through all of the non-digit cells
AND ALSO must visit each region once at
ONLY the respective region number cell,
which follows in the increasing order before back to 1 again (i.e. 1 -> 2 -> ... -> 7 -> 1).
Whenever the loop goes through a region number cell, it must make a 90 degrees turn at that cell.
- A cell with arrow[s] in it contains digit that's equal to the
combined amount of cell borders that the loop goes through in the indicated direction[s],
including the borders of arrow cells as well if available.
- Every given empty cell doesn't contain digit or loop segment at all.
An example of how the rules work can be found below. It's not an actual puzzle, but rather acts as an illustration for how the main concept works and also how the arrow rule works.
Puzzle: Penpa plus -
Sudokupad
The answer check in penpa link will activate once all of the digits are correctly filled and also the loop is correctly drawn. For now, good luck and have fun solving!
Zuletzt geändert am 18. Februar 2025, 11:01 Uhr