XV*Magic 2
(Eingestellt am 6. Dezember 2024, 16:09 Uhr von NurglesGift)
Normal sudoku rules apply.
Cells connected by an X must sum to 10.
Cells connected by an V must sum to 5.
All X's and V's are given.
There is a 3x3 magic square somewhere in the grid.
(A magic square is a 3x3 square with the digits 1-9 where all rows, columns and diagonals have the same sum)
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Feel free to recommend this puzzle to anyone.
Feel free to take special rules for your own puzzle.
Feel free to give feedback.
Bless you!
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Lösungscode: give the digits of row 4 (left to right)
Kommentare
am 22. Dezember 2024, 18:33 Uhr von Zerobrain
Love this series. Thanks
am 14. Dezember 2024, 05:12 Uhr von virus_dave
Wow, very lovely puzzle! I had to use the only possible placing of the magic square to place the last 5, then it was very satisfying to use that to fill in the digits on the whole board!
@JohnBoggs Assuming you've identified high/low cells correctly, there's only one possible orientation of the magic square that will fit the polarity. From that one orientation you can assign all the digits.
am 13. Dezember 2024, 08:23 Uhr von rudaass
I could simply do negative XV every day, especially this great. Thank you.
am 10. Dezember 2024, 00:02 Uhr von stramosk
really satisfying to colour everything and then place all digits for each colour at once!
am 7. Dezember 2024, 18:19 Uhr von dtoto
Phenomenal addition to this series!
am 7. Dezember 2024, 14:15 Uhr von mihel111
Great idea. Lovely puzzle.
Thanks a lot.
am 7. Dezember 2024, 12:36 Uhr von kagiso
I struggled so much with this but really enjoyed it!
am 7. Dezember 2024, 03:23 Uhr von gnidan
loved how the logic for placing the magic square intertwines with the logic for assigning colors to X pairs.
please do more of these!
am 6. Dezember 2024, 21:35 Uhr von briansometimes
Great idea with the magic square to resolve digtis. I'll say this is 2 star difficulty if you're an experienced nurgler, and 3 if you aren't.
Edit: SPOILER help for JohnBoggs and others. Magic squares are very restricted, e.g. they always have 294 or 492 in one of their "sides". If your colouring differentiates between high (6-9) and low (1-4) digits, it's easy to spot which side can be a 9 in the middle flanked by low digits, and the rest unravels from there.
am 6. Dezember 2024, 20:29 Uhr von thebanterman
Nice beautiful logic throughout
