Logic Masters Deutschland e.V.

Projected Cave

(Eingestellt am 10. August 2024, 20:16 Uhr von KNT)

Shade some cells in the grid such that all unshaded cells are orthogonally connected, and all orthogonally connected groups of shaded cells touch the edge of the grid.

Place into every unshaded cell the number of unshaded cells seen in all four directions, including itself, at that location, where shaded cells obstruct vision. Numbers must not be placed into shaded cells.

Clues outside the grid indicate the sums of connected groups of numbers in the respective row or column, in order, where shaded cells serve as delimeters between groups. A question mark can be any positive number.

A 6x6 example is provided:

SudokuPad

penpa+

Lösungscode: The lengths of the shaded blocks in Row 2, Row 4, Column 3, Column 7. X for greater or equal to ten.


Gelöst von Niverio, Paletron, wooferzfg, Jakhob, Myxo, tuturitu, ibag, h5663454, ONeill, johnyzzh, jkuo7, Agent, Mr_tn, Jesper, MagnusJosefsson, madhupt, Hazem-77, AnnaTh, r45, ffricke, Alex, ch1983, misko, dunder, LeiZ123321, Samish, akamchinjir, Counterfeitly, RJBlarmo, Snookerfan, filmore
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Kommentare

am 20. Oktober 2024, 14:22 Uhr von Snookerfan
Superb and fun! Thank you

am 5. September 2024, 02:28 Uhr von Samish
Wow, impressive and lovely minimalism!

am 28. August 2024, 17:35 Uhr von LeiZ123321
really fun to solve!

am 13. August 2024, 16:22 Uhr von madhupt
Magnificent! A mighty satisfying solve.

am 13. August 2024, 09:55 Uhr von MagnusJosefsson
Fantastic! Very satisfying and fun!

am 12. August 2024, 21:58 Uhr von Jesper
That was awesome, great ruleset :)

am 11. August 2024, 14:39 Uhr von Agent
Very fun and impressive puzzle!

am 11. August 2024, 12:49 Uhr von ONeill
Fun and interesting ruleset :)

am 11. August 2024, 08:54 Uhr von ibag
Wow! I'm really impressed by this great construction!!!

am 10. August 2024, 22:24 Uhr von Myxo
Cool!

am 10. August 2024, 21:00 Uhr von wooferzfg
A bit trickier than I expected, but really cool and fun to figure out - especially the ending.

Schwierigkeit:4
Bewertung:99 %
Gelöst:31 mal
Beobachtet:5 mal
ID:000JAL

Lösung abgeben

Lösungscode:

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