Logic Masters Deutschland e.V.

Nurikabe Kurotto

(Eingestellt am 12. Juni 2024, 10:57 Uhr von Paletron)

Rules:
  • Shade some cells so that all shaded cells form one orthogonally connected area and no 2x2 region is entirely shaded.
  • Orthogonally connected areas of unshaded cells contain at most one clue, which indicates the size of the unshaded area.
  • A clue in a shaded cell represents the total count of unshaded cells in orthogonally connected groups sharing an edge with that cell.
  • A '?' represents any number.
Puzzle:

Lösungscode: Lengths of shaded blocks in Row 12 and Column 12

Zuletzt geändert am 12. Juni 2024, 13:21 Uhr

Gelöst von Niverio, jkuo7, ONeill, CJK, KNT, Jesper, Mr_tn, h5663454, Agent, wooferzfg, misko, puzzler05, MaizeGator, Piatato, GoogleEnPassant, Niku, uvo, stream, Christounet, Bellsita, AsgarArn, ascension, mnasti2
Komplette Liste

Kommentare

am 21. August 2024, 23:31 Uhr von AsgarArn
Great puzzle! Had ha hard time to wrap my head around the rules. Then afterwards te rules seem good enough Maybe it is just that i do these so seldom. A small example would be great.

But after the initial looking for example in other simillar puzzles this was magnisifent, had some quite fun challanges along the way!

am 19. Juli 2024, 09:15 Uhr von Christounet
Great ! Enjoyed that. Thanks :)

am 18. Juni 2024, 09:14 Uhr von Piatato
Very nice!

am 16. Juni 2024, 20:38 Uhr von MaizeGator
I loved the variety of logic showcased in this puzzle. It felt like I rarely applied the same "trick" more than once. Loved it!

am 13. Juni 2024, 07:04 Uhr von wooferzfg
Very fun, thanks!

am 12. Juni 2024, 22:43 Uhr von Jesper
Really enjoyed it, interesting ruleset!

am 12. Juni 2024, 21:28 Uhr von KNT
extremely good, thanks!

Zuletzt geändert am 12. Juni 2024, 12:10 Uhr

am 12. Juni 2024, 12:03 Uhr von Niverio
Very cool puzzle! Although even though I got answer check in Penpa+, the code I enter isn't accepted.

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Fixed, thanks!

Schwierigkeit:4
Bewertung:96 %
Gelöst:23 mal
Beobachtet:1 mal
ID:000IH3

Lösung abgeben

Lösungscode:

Anmelden