Deja vu
(Eingestellt am 9. Juni 2024, 12:32 Uhr von Al Fresco)
Abnormal Sudoku rules apply. Each 3x3 box contains a full set of digits 1-9. However each row and column contains 8 different digits.
Each row, column and box contains a repeater cell. A digit in a repeater cell must repeat in it’s row and column. Each digit 1-9 appears in one repeater cell.
Cages may not contain the same digit more than once and the digits sum to the given cage total. Digits separated by an x sum to 10.
Play online
Lösungscode: Row 2
Kommentare
am 9. Juni 2024, 20:47 Uhr von Briks
Finally... liked it very much
am 9. Juni 2024, 18:03 Uhr von OutOfMyMindBRB
What a brilliant puzzle! Severe "damage" to the usual scanning... had to restart 5 times until i got the hang of it, quite a challenging and fun solve!
BTW, the solution check does not work for this one.
am 9. Juni 2024, 16:42 Uhr von Al Fresco
Updated the wording in the rules.
Appologies for the unclear wording.
am 9. Juni 2024, 15:54 Uhr von sujoyku
No Briks, I agree that the wording of the rules could be more clear. But I guess it should be possible that in row 1 the 23 and the 21 cage share a repeated digit. But inside of one cage no digit may repeat.
am 9. Juni 2024, 14:53 Uhr von Briks
I any case there are double digits in the two cages which isn't allowed by the rules.
am 9. Juni 2024, 14:34 Uhr von sujoyku
I think it is meant differently, Briks. If I understand the rules correctly, the repeater cell may be in a cage. But then the other instance of that digit in the row/column may not be contained in that same cage.
am 9. Juni 2024, 13:37 Uhr von Briks
It is not possible to fill the cages in the first row (23, 21) with digits when there is no repaeater cell in one of the cages.
