Logic Masters Deutschland e.V.

The following puzzle - or I should say 'puzzle collection' - is a reworked version of my abandoned 6x6 pack in the past and yes, this is also a pack containing six 6x6 (mostly) sudoku puzzles with extra rules. That pack was meant for a 2-year anniversary of myself stepping into the puzzle setting world for the first time but after an official revisit of it last month, I felt like it wasn't as remarkable as I'd thought it would be so I thought that I should plan for a proper rework of it. Talk about coincidences for a special post before almost reaching my 3-year mark there...


For this reworked version, all of the puzzles in this one have something special in them while still maintain some doses of joy in each of them along the way. I feel like some of the ideas in here will inspire someone to explore them more in bigger sizes :)


I won't try to prolong this preamble too much and just let this pack show its true self over here. I hope you enjoy this special treat (oh, and maybe a funny hidden 'easter egg' in here too x} ) !

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The difficulty of the puzzles in this pack will range from 2/5 to potentially lower side of 4/5, and the overall difficulty is judged by the average of all six puzzles. The later threes are relatively harder than the first threes and I actually recommend one to spend a short while reading their rule sets and visualizing how they work overall (along with some provided examples).




Rules: Normal 6x6 Sudoku rules apply to puzzles 1 to 5: every row, column and 3x2 box contains digits from 1 to 6 each once. An exception for puzzle 6 will be detailed later.                                                          .
Variants included in this pack are:


1) Indexer Sum:
- A clue outside the grid shows the sum of X and the digit in the Xth cell from its respective row/column, where X is the value of the cell right next to that clue.
- All of the clues are ciphered and it's required to deduce their values. Same letters correspond to same value and different letters correspond to different values. (2B means 2 times B, 3A means 3 times A)


2) Entropic + XY Difference:
- Along a light orange line, any sequence of three sequential cells must contain one digit from set {1,2}, one digit from set {3,4} and one digit from set {5,6}.
- If there's a diamond between two adjacent cells within a row, the absolute value of the difference of two digits from those two cells must equal to the value of the first cell in that row (i.e. row X column 1).
- If there's a diamond between two adjacent cells within a column, the absolute value of the difference of two digits from those two cells must equal to the value of the first cell in that column (i.e. row 1 column X).
- Not all possible diamonds are given.


3) Equaline + Doublers:
- Six cells in the grid must be marked as 'doublers' so that each row, column and box must contain exactly one doubler cell. Each digit from 1-6 must appear once in the set of doublers.
For the purpose of evaluation, a doubler cell's value is determined as twice the value of the digit in that cell.
- Along a light green line, the values of all digits sum to the same total, which is required to be deduced. Note that digits can repeat along a line if allowed by other rules.


4) X-sum Doubled Limit vs Parity Party: Each outside clue belongs to exactly one of the two following clue types, and it's required to deduce which one is which:

- X-sum Doubled Limit: An outside clue shows the sum of the first X cells from that clue's direction PLUS the value of the Xth cell also from that direction in its row/column, where X is the value of the cell next to that clue.
- Parity Party: An outside clue shows the sum of the digits UP TO AND INCLUDING either the first even digit or the first odd digit found from that clue's direction in its row/column. It's possible that a single digit clue might show the value of the first digit only.

Some examples of how both clue types work can be found in this link.


5) Build Your Own Sloop - Motherboard:
- Draw a one-cell wide loop that travels through some cells in the 6x6 grid. The loop doesn't intersect itself but may touch itself at some points (orthogonally or diagonally).
- A digit in a cell with red arrow[s] equals to the combined amount of cells along the indicated direction[s] that belong to the loop.
- A digit in a cell with blue arrow[s] equals to the combined amount of cells along the indicated direction[s] that DO NOT belong to the loop.
- An outside clue of a row/column shows how many grid borders the loop goes through within that row/column (of course, not including the 6x6 grid border).


6) Chaos Construction - The Beginning and The End:
- In the 6x6 grid, every row and column contain digits 1-6 each once. Divide the 6x6 grid into 6 orthogonally connected regions so that each region also contains digits 1-6 each once.

- An outside red clue of a row/column shows the sum of either the first continuous group of cell[s] belonging to the first region or the last continuous group of cell[s] belonging to the last region that red clue sees in its row/column.
- An outside blue clue of a row/column shows the sum of two cells separated by either the first region border or the last region border within that row/column (not including the 6x6 grid border).
- In addition, within a row/column:
+ If its red clue works for the FIRST region then its blue clue must work for the LAST region border and vice versa.
+ If its red clue works for the LAST region then its blue clue must work for the FIRST region border and vice versa.

- ?? indicates an unknown two-digit integer sum and an asterisk (*) indicates an unknown non-zero integer sum of that outside clue (which can be either single digit or multiple digits).

Some examples of how the concept works can be found in this link.

Puzzle:

F-puzzle:   Puzzle 1  -  Puzzle 2  -  Puzzle 3  -  Puzzle 4  -  Puzzle 5  -  Puzzle 6

Penpa+:   Puzzle 1  -  Puzzle 2  -  Puzzle 3  -  Puzzle 4  -  Puzzle 5  -  Puzzle 6

CTC app:  Puzzle 1  -  Puzzle 2  -  Puzzle 3  -  Puzzle 4  -  Puzzle 5  -  Puzzle 6



After this entire project, I shall return to finishing my ultimate solving quest that I've been stalling for a while and starting to appreciate everyone else's works more (along with a couple of old gems here as well, I think).
For now, good luck and have fun solving!