Logic Masters Deutschland e.V.

4 Circles (yin yang + loop + fillomino)

(Eingestellt am 9. April 2024, 04:23 Uhr von Star216)

This is a combination of yin yang, loop, and fillomino, Enjoy!

Rules:

Fillomino: Split the grid into regions. Inside each cell enter the size of the region it is in. No two regions of the same size can be next to each other.

Yin Yang: Shade some cells such that all shaded and non shaded cells from orthogonally connected area and no 2 by two area is shaded or unshaded. Every fillomino region is all shaded or all unshaded

Loop: Draw a loop through the centers of some cells. The loop alternates passing through shaded and non shaded cells. Moreover, the loop can only pass through each region once.

Cells in a circle are on the loop. Cells that have a shaded square must be even. The grey line reads the same forwards and backwards

Solve with SudokuPad

Lösungscode: Row 5 from left to right

Zuletzt geändert am 9. April 2024, 18:43 Uhr

Gelöst von SKORP17, josebastian8, MagnusJosefsson, Mark Sweep, MicroStudy, topoi, Jesper, JustinTucker, MaizeGator, misko, Torvelo, SparklePuzzle, geswat, dogfarts, gdc, puzzler05
Komplette Liste

Kommentare

am 10. April 2024, 19:48 Uhr von topoi
Really enjoyed this puzzle! Heads up, there is an error in the solution checker.

am 9. April 2024, 18:43 Uhr von Star216
last fix hopefully

am 9. April 2024, 18:27 Uhr von Star216
Fixed link as well

am 9. April 2024, 18:10 Uhr von Star216
Added all regions shaded or unshaded

Zuletzt geändert am 9. April 2024, 18:22 Uhr

am 9. April 2024, 17:41 Uhr von MagnusJosefsson
Actually a great little puzzle! But unfortunately, as josebastian8 also has written in a hidden comment, the description of the rules is currently missing the requirement that each fillomino region is either entirely shaded or entirely unshaded.

Fixed! Will work on fixing in the sudokupad soon too!

am 9. April 2024, 14:24 Uhr von Star216
changed difficulty to 3*

am 9. April 2024, 04:42 Uhr von Star216
Fixed typoes

Schwierigkeit:3
Bewertung:81 %
Gelöst:16 mal
Beobachtet:1 mal
ID:000HML

Lösung abgeben

Lösungscode:

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