Normal Fillomino rules apply. (Divide the grid into regions, so that no two orthogonally adjacent regions have the same size. In each cell, insert the size of the region containing it.)
Digits in a circle count how many circles contain that digit. No Fillomino region contains more than one circle.
Solution code: Digits in circles read left to right, top to bottom. No spaces or other delimiters.
on 14. March 2024, 15:39 by marcmees
3/4 smooth. 1/4 at the end gets tougher - needed some intuitive drawing. Nice. Thanks.
on 14. March 2024, 15:26 by Snookerfan
Excellent puzzle! Thank you
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