Normal Fillomino rules apply. (Divide the grid into regions, so that no two orthogonally adjacent regions have the same size. In each cell, insert the size of the region containing it.)
Digits in a circle count how many circles contain that digit. No Fillomino region contains more than one circle.
Lösungscode: Digits in circles read left to right, top to bottom. No spaces or other delimiters.
am 14. März 2024, 15:39 Uhr von marcmees
3/4 smooth. 1/4 at the end gets tougher - needed some intuitive drawing. Nice. Thanks.
am 14. März 2024, 15:26 Uhr von Snookerfan
Excellent puzzle! Thank you