This mashup of Yajilin and Wittgenstein Briquet doesn't quite follow either ruleset strictly. It was the result of WPC speedsetting competition. I quite like the result. Enjoy!
Rules
Shade some cells in the grid so that all shaded cells are part of 1x3 rectangle groupings of shaded cells.
All number clues indicate the amount of rectangles in the 4 orthogonally adjacent cells.
Draw a single non-branching, non-crossing loop that goes through all empty unshaded cells.
Cells with numbers are not shaded, and are not part of the loop.
If a number clue contains an arrow, the arrow indicates the amount of shaded cells in its direction.
Links
Penpa + Link
Lösungscode: Count the number of cells with fully vertical loop path in each column, left-to-right; then count the number of horizontal bricks in each row, top-to-bottom (24 digits)
am 7. November 2023, 16:01 Uhr von CHalb
@jessica6: Yes, you got that right so far. And what I didn't remember till some help: Bricks may touch each other orthogonally. :)
am 7. November 2023, 13:29 Uhr von jessica6
Do I understand this correctly?
- all number clues, with and without arrow, count number of bricks in adjacent cells
- clues with arrows additionally count cells (not bricks) in direction of arrow
can bricks touch each other orthogonally?
am 7. November 2023, 00:17 Uhr von wisty
very fun puzzle, thanks! brought a smile to my face. also an inspiring yajilin variant as a setter, curious what similar ideas might work well
am 4. November 2023, 21:12 Uhr von Christounet
Fun puzzle ! Thanks :)
am 30. Oktober 2023, 23:21 Uhr von wooferzfg
Fun and easy!
am 30. Oktober 2023, 01:33 Uhr von mnasti2
I haven’t done yajilin or Wittgenstein briquet but that was fun!