Logic Masters Deutschland e.V.

1234 (anti-king,anti-knight,negative XV)

(Eingestellt am 22. Juni 2023, 10:58 Uhr von William Cheese)


Rules:
  • Normal sudoku rules apply.
  • X/V Two digits separated by an X must sum to 10. Two digits separated by a V must sum to 5. (These digits are orthogonally adjacent.)All possible XV are given.
  • Anti-knight A square must contain a digit different from every other square a knight’s move away (2 over and 1 across).
  • Anti-king A square must contain a digit different from every other square a king’s move away (sharing a vertex).

F-puzzles link: Click Here

Lösungscode: Column 1, row 9

Zuletzt geändert am 22. Juni 2023, 11:36 Uhr

Gelöst von Senip, annnz, Lorff, jalebc, VeTaurus, Qodec, XhcnoirX, Fishhh, sbc, kublai, flaemmchen, jgarber, belfieldtj, marcmees, thoughtbyte, dodomos, zuzanina, 333sudoku333, bnoblett, asver, Hondor64, ... PinkNickels, Awoobledoople, Thomster, saskia-daniela, 0123coolkid, PippoForte, JSmoove1099, chain.reader, dingledork, LachyDachy, mattnburris, Montikulum, pepe74287, BenClancy, Csmith928, Dez256
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Kommentare

am 14. Januar 2024, 00:14 Uhr von chain.reader
awesome! amazing how this even works

am 30. Juni 2023, 20:07 Uhr von 99%Sneaky
Nice interplay between the constrains.

am 26. Juni 2023, 03:20 Uhr von sacklunch
Great puzzle, very interesting. The solution code worked for me.

am 23. Juni 2023, 10:51 Uhr von KcDaRookie
Same as starstorm. Have a solution but the code isn't accepted.

am 22. Juni 2023, 22:59 Uhr von Timwi
Awesome puzzle! Not as easy as the rating suggests, but I enjoyed it thoroughly.

Here’s a link to play this puzzle on Zinga: https://zinga.timwi.de/czHfllCJdMZR8zXeHZVbh6

am 22. Juni 2023, 16:53 Uhr von Starstorm
The solution code doesn't seem to work, even though I have a complete grid that satisfies all rules

am 22. Juni 2023, 11:36 Uhr von William Cheese
edit

Zuletzt geändert am 22. Juni 2023, 11:33 Uhr

am 22. Juni 2023, 11:20 Uhr von jalebc
code?
-----
Did the code not work?

Schwierigkeit:1
Bewertung:82 %
Gelöst:93 mal
Beobachtet:8 mal
ID:000E90

Lösung abgeben

Lösungscode:

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