Biggest Neighbour Sudoku
Dieses Rätsel ist von Realshaggy WSC2019 inspiriert.
Solve online in Penpa+ (thx Steven R!)
Verwende die üblichen Sudoku-Regeln.
Pfeile zeigen auf die größte Ziffer in den (bis zu vier) orthogonal benachbarten Kästchen.
Lösungscode: Zeile 4, gefolgt von Spalte 1
am 6. Mai 2022, 01:38 Uhr von Krokant
Wonderful puzzle. :)
am 14. April 2022, 20:34 Uhr von Orpheus
Wow, what a fun puzzle! I enjoyed every twist and turn of this thing!!
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Reply: Thanks!
am 13. April 2022, 15:26 Uhr von glum_hippo
I solved this while eating a hard-boiled egg. Not easy, but with some very enjoyable logic! Recommended!
am 13. April 2022, 06:49 Uhr von henrypijames
3⅔ difficulty for me, even though I found a way to visualize and pencilmark the constraint very effectively:
https://tinyurl.com/y2fnf4pq
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Reply: Looks like you are a painter! :-)
am 13. April 2022, 03:40 Uhr von Richard
Added link for online solving. Thx Steven R!
am 13. April 2022, 01:08 Uhr von Steven R
Penpa with answer check: https://tinyurl.com/4vue38j8
am 13. April 2022, 00:58 Uhr von Greg
@Realshaggy The cell pointed at by an arrow is larger than the other 3 cells orthogonally adjacent to the cell containing the arrow.
E.G R2C1 is greater than R3C2 and R4C1.
am 13. April 2022, 00:08 Uhr von Realshaggy
Hi Richard, I'm a little bit confused by your formulation of the rules. What happens, if there are multiple largest neighbours? The original rules state that in this case, all arrows are given. Your formulation "THE largest digit" suggests that in this puzzle it can be assumed to be unique?
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@Realshaggy: you are right with your assumption, although it shouldn't be an assumption but the exact interpretation of the rules. THE means indeed unique.
I ended up with a puzzle without cells having multiple arrows, so I thought it would be more confusing to write about 'all digits' when there are no cells having such constraints.
First I tried to find a useful place to add an extra cell with two arrows, but couldn't find one that didn't disturb the intended solve. So I chose for the second best option: adjust the rules and the name of the puzzle (without S).