This is the fifth puzzle in a series of seven anchor sudoku puzzles.
I really like this one, however the break-in is quite tricky, so I included some minor hints to push you in the right direction if you get stuck.
Anchors are like arrows, except you subtract the smallest digit from the sum of the other digits. So for example an anchor with a 5 in the square, and 4,2,3 in the chain would be valid because 5=4+3-2. Repeat digits are allowed so 5,5,1,1 would also be valid because 5=5+1-1.
Previous PuzzlesStandard sudoku rules apply.
Subtracting the smallest number along an anchor from the sum of the other numbers equals the number in the square cell.
Solve the puzzle at https://f-puzzles.com/?id=yfpww3f2
HintsHint 1 for break-in: The break-in uses parity
Hint 2 for break-in: The sum of all digits on an anchor is even, and the parity of the square is the same as the parity of the sum of the other digits on the anchor.
Lösungscode: Columns 1 and 2
am 19. Juni 2021, 13:36 Uhr von Piatato
Great puzzle, yet again. :-)
am 18. Juni 2021, 22:37 Uhr von polar
Very nice! Enjoyed the different break in on this one :)
Schwierigkeit: | |
Bewertung: | N/A |
Gelöst: | 5 mal |
Beobachtet: | 7 mal |
ID: | 0006P2 |