Odd Parity Circles Sudoku
Dieses Rätsel ist von bigger inspiriert.
Solve online in F-Puzzles (Thx tubahat!) or in Penpa (Thx Nick Smirnov!).
Verwende die üblichen Sudoku-Regeln.
Überall wo sich in einem 2x2-Bereich genau 3 gerade oder 3 ungerade Ziffern befinden, ist dies durch einen Kreis auf der Kreuzung der Gitterlinien dieses Bereichs markiert. Die Ziffern in dem Kreis müssen auf einer Diagonale in diesem Bereich platziert werden. Innerhalb eines 2x2-Bereichs dürfen sich Ziffern wiederholen.
Lösungscode: Zeile 4, gefolgt von Spalte 1.
am 19. Dezember 2021, 08:04 Uhr von Richard
Added links for online solving. Thx tubahat and Nick!
am 22. November 2021, 18:31 Uhr von Nick Smirnov
Penpa:
https://git.io/J1QL0
Unlike tenaliraman I think this sudoku decreases in terms of difficulty. The first steps include some tricky bits, but after that it becomes very easy.
am 14. Dezember 2020, 18:43 Uhr von Bankey
Delightful variant ! Thanks, Richard!
am 10. Dezember 2020, 14:19 Uhr von telliott
Great puzzle, thanks. The negative constraint rules supreme in this one.
am 10. Dezember 2020, 11:55 Uhr von tenaliraman
I love how the puzzle increases in terms of difficulty as you keep solving the puzzle. Very educational in how a puzzle must be designed :-)
am 9. Dezember 2020, 22:04 Uhr von SudokuExplorer
Delightful logic! Thanks for making yet another very enjoyable puzzle :-)
am 9. Dezember 2020, 17:04 Uhr von washyleopard
@tubhat
When you click export just click copy compressed link.
https://f-puzzles.com/?id=y3m8ll76
am 9. Dezember 2020, 16:56 Uhr von tubahat
https://f-puzzles.com/?id=y3m8ll76
am 9. Dezember 2020, 15:20 Uhr von Fedo
I had fun solving it, thank you for this!
am 9. Dezember 2020, 13:44 Uhr von PetLov
So OK, I feel like such an idiot :-)
Reading the rules properly is a good idea.
Thank you all for clearing this up to me.
am 9. Dezember 2020, 13:31 Uhr von cdwg2000
@PetLov
It can be solved by using negative restrictions. It is not recommended to use uniqueness before the additional conditions are used.
am 9. Dezember 2020, 13:28 Uhr von bigger
I don't think there is a deadly pattern. 579 and 6 have different parity, and the rule said 'in all case'. so it's not possible, unless the pattern strictly has one parity
am 9. Dezember 2020, 12:38 Uhr von PetLov
This puzzle is nice, however I ended up with a deadly pattern of 5, 7, 6 & 9.
@PetLov: what do you mean with a deadly pattern? Guessing is not necessary and the puzzle has one unique solution... ?!?
***In my solution, which may be incorrect somewhere but correct enough to enter the solution code, I can swap the digits in R1C4 & R1C5 and all the digits that follows after that swap and still get a valid solution. As I said, I probably missed something somewhere.
***Thank you cdwg. That is indeed what I missed :-)
am 9. Dezember 2020, 01:00 Uhr von CountSudokula
Richard, can't wait for # 300... maybe it should be called THIS IS SPARTA!! :)