Invisible Slingshot Killers and Silent Killers Sudoku
(Eingestellt am 22. August 2020, 10:44 Uhr von stephane.bura)
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This is a harder Slingshot puzzle. If you're not familiar with this ruleset, consider trying another one is this series first. Normal Sudoku rules apply. If an arrow is present in a cell, the digit in the cell the arrow comes from appears in the grid in the direction of the arrow at a distance of N cells, where N is the digit in the arrow's cell. Furthermore, the arrow creates a virtual killer cage from the arrow cell to the projected digit's cell. The sum of the digits in the cage is the product of the arrow cell's digit and the projected digit. The grid is toroidal. So, for instance, the R1C1 arrow creates a slingshot with the value in R1C9 and its virtual cage continues in R9C1 and goes up. The digits in each visible killer cage in the grid sum up to the same total as the slingshot cage of the arrow it contains. Digits may not repeat in each of these cages - but since invisible and visible cages overlap, there are repeats between them. Penpa-Edit link for this puzzle to play it online. |
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Lösungscode: Row 7, row 8
Kommentare
am 7. August 2021, 16:13 Uhr von Mody
Hat mir gut gefallen. I liked it very much.
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Thanks Mody :)
am 22. August 2020, 19:47 Uhr von henrypijames
This series is now one of favorites. Please do post more (and all you've created) here.
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Alright! :)
I have one more unpublished puzzle that feels very easy to me but caused many problems to the people who tried it. I refrained from posting it for this reason but I will.
am 22. August 2020, 18:03 Uhr von henrypijames
I assume a slingshot of 9 is still not allowed? Because nothing in the rules says a virtual killer cage cannot overlap onto itself - and in a toroidal grid, it can.
Edit: Oh wait - a 9 slingshot would mean the slingshot itself becomes the target, and more importantly, is also equal to the source right beside it, which is not allowed by sudoku. Feel free to hide this comment if you think everyone should discover this logic on his own.
