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Dominorätsel - das Zweite

(Published on 17. December 2009, 17:00 by Carambu)

Es handelt sich um eine normale Dominozerlegung. Es sind die Kanten der Dominosteine einzuzeichnen, so daß jeder Dominostein von 0-0 bis 6-6 genau einmal vorkommt.

Solution code: Für die Ziffern 0-6 die Anzahl der horizontalen Dominosteine.

Last changed on on 17. December 2009, 17:25

Solved by Luigi, PRW, pwahs, flaemmchen, Alex, sternchen, lolo, Toastbrot, saskia-daniela, CHalb, Nothere, cornuto, hopppe, logik66, Statistica, Richard, pokerke, zuzanina, Javier Rebottaro, Maulef, pin7guin, ... NikolaZ, Pfannkuchener, Dandelo, Krokant, AndreasS, NinaS, drolli38, athin, misko, shinkimancer, Greg, Raistlen, CJK, Dugong, hibye1217, jogerth, Bearpig, nmk1218, abadx, Jordan Timm, DK_48
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Comments

on 21. July 2022, 14:02 by Bearpig
Penpa: https://tinyurl.com/2acn2akh

on 18. December 2009, 18:47 by Calavera
Wenn ich doch bloß fähig wäre, die horizontalen Steine richtig zu zählen... ;-)

on 18. December 2009, 08:32 by rubbeng
Thank you, flaemmchen

on 17. December 2009, 18:22 by flaemmchen
@rubbeng:
First you have to write the number of horizontal domino-pieces, which contain a "0", then the number of horizontal domino-pieces, which contain a "1" etc.

Last changed on 17. December 2009, 17:49

on 17. December 2009, 17:37 by rubbeng
I don't understand "Lösungscode". Thanks

For each cypher 0-6 the number of horizontal domino pieces. The domino pieces 0-0, 1-1, 2-2, 3-3, 4-4, 5-5, 6-6 are only counted once.

on 17. December 2009, 17:26 by Luigi
Merci ;-)

on 17. December 2009, 17:24 by Carambu
Sorry, hab's gerade korrigiert.

Difficulty:1
Rating:71 %
Solved:159 times
Observed:5 times
ID:0000E6

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