Logic Masters Deutschland e.V.

Avian Variant

(Published on 11. February 2026, 19:22 by Jrosas)

THE RULES:

Ordinary sudoku rules apply: place the digits 1 through 9 in each row, column, and 3x3 bold outlined box.

Ornithologically adjacent rule: Some orthogonally adjacent cells are separated by birds. Each such pair of orthogonally adjacent cells contain a pair of ornithologically related digits.

Each variety of bird designates an ornithological relation between a particular pair of orthogonally adjacent digits. For example, all pigeons might separate all the 1/2 pairs, and all peacocks might separate all the 2/3 pairs. This is only a hypothetical example. As you can see, there are no pigeons or peacocks in the grid.

Everywhere in the grid any particular pair of ornithologically related digits appear in orthogonally adjacent cells they are separated by their particular bird. That is to say, all birds are given.

Sven Neumann’s Sudokupad

Solution code: Top row left to right


Solved by ketchup_monster, Qodec, hige, dzamie, SKORP17, RobJH, Hierophis69, Chefofdeath, Piff, butch02, thek3nger, baltoguy
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Comments

on 12. February 2026, 01:01 by Chefofdeath
BIRB!

on 12. February 2026, 01:01 by Chefofdeath
BIRB!

on 11. February 2026, 22:28 by Jrosas
I intended to rate this two stars difficulty. I tried changing it twice. If you think it’s rated too hard, try reading the instructions out loud to add to the difficulty.

on 11. February 2026, 22:04 by Qodec
Loved those bird interactions!

on 11. February 2026, 21:33 by ketchup_monster
Easier solve than I expected when I started. But way more fun than I imagined :)

Difficulty:3
Rating:N/A
Solved:12 times
Observed:0 times
ID:000NV5

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Solution code:

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