Wichtels (später) Rätselsommer 2024 (13 und Schluss): Doppelte Freude
(Published on 29. October 2024, 20:25 by wichtel)
Place the 12 pentominoes into the grid, so that all of them are touching diagonally, but not orthogonally. The pentomino cells are shaded. An arrow in a cell points to the second-nearest shaded cell. If more than one shaded cell is equally far, then there will be one arrow for each applicable direction. Cells with arrows must not be shaded. Given numeric clues may lie on shaded or on unshaded cells.
Place a number in each cell with arrows, which indicates the distance to the second-nearest shaded cell or cells.
The remaining 120 cells form a valid Meidjuluk (N=15) puzzle. The Meidjuluk consists of a single contiguous (i.e., orthogonally connected) Viginticentomino. Numbers in the Meidjuluk area, including those with arrows, are Meidjuluk clues. The Meidjuluk does not contain any zeros.
To solve the Meidjuluk, divide the region into areas of size 1 to 15. Each size occurs exactly once, and each region must only contain factors of its size, with none appearing more than once in the same region. For example, the region of size 6 may contain any combination of the numbers 1, 2, 3, and/or 6, including none of these.
Finally, draw a loop into the diagram which moves from one cell center orthogonally to the next, without crossings and without visiting any cell more than once. Each Meidjuluk region is visited exactly once, and the same goes for each pentomino that doesn't contain a zero. Three segments of the loop are already given. In every Meidjuluk-Region the loop must visit a number of cells corresponding to a factor of the region size. Thus the 15-region must contain 1, 3, 5, or 15 loop cells. In a pentomino with a given digit, the loop must visit that number of cells. Cells with numbers may, but are not required to, be traversed by the loop.
Solution code: In row 2, first the lengths of the horizontal stretches of loop, then for each cell the size of the enclosing Meidjuluk Region (which might be a two-digit number) or the letter corresponding to the enclosing pentomino. The same for column 10 with regard to vertical stretches.
Comments
on 27. November 2024, 18:47 by ibag
@zuzanina: Schau dich halt mal ein bißchen in der Umgebung um. ;-)
on 27. November 2024, 17:22 by ibag
@zuzanina: 1. Ja!!! ;-)))
2. Im Prinzip ja. Aber Pentominos mit einer 0 dürften natürlich nur eine weitere 0 enthalten.
on 27. November 2024, 17:04 by zuzanina
Hmmm, sieht schön aus. Aber ein paar Fragen stelle ich mir noch:
1. Haben die grünen Felder eine Bedeutung?
2. Darf ein Pentomino mehrere Zahlen enthalten? Also gleiche Zahlen bzw. das mit der Null noch andere Zahlen?
on 21. November 2024, 15:10 by ibag
;-))
on 21. November 2024, 14:23 by Nensche777
Finally figured it out. It is really a nice puzzle once the rules are understood.
@PrimeWeasel: your example will certainly help other solvers.
@ibag: der Aha-Effekt ist nun da, wie prophezeit. :)
on 20. November 2024, 07:20 by PrimeWeasel
https://tinyurl.com/23lmlu38
Here's an example of how to interpret the rules, mainly notice that there is no arrow pointing to the right
I'd also like to make clear that I told the setter that I did not think the rules were very clear regarding these arrows.
R5C3 could even be black here
@Nensche777 'Do you mean that as soon as I see a black cell in a direction, I ignore what’s “behind” it?' Yes
on 19. November 2024, 23:47 by ONeill
I gave up a while ago after trying to interpret the arrow rule many different ways and it breaking immediately every time
on 19. November 2024, 23:32 by ibag
@Nensche777: ich bin anfangs auch erstmal über die Formulierung gestolpert. Falls das ein Trost ist.
on 19. November 2024, 15:41 by PrimeWeasel
@Nensche777 Arrows point to directions with the second nearest cells. If a direction has a nearest cell, there will never be a second nearest cell in that same direction. R10C11 being black doesn't exclude R11C11 from being black too.
on 19. November 2024, 07:24 by ibag
@PrimeWeasel: Nensche777 can't read your comment. You have to write visible..
on 3. November 2024, 09:22 by ibag
Da hatte ich jetzt sogar die vierfache Freude, weil ich ja niemals was aufhebe (und schöne Rätsel auch ein weiteres Mal Spaß machen).
Vielen lieben Dank meinem Wichtel! Das war ein ganz wunderbares, sehr individuelles und kommunikationsförderndes Geschenk.
on 30. October 2024, 16:51 by PrimeWeasel
This is just to say
I have eaten
the plums
that were in
the icebox
and which
you were probably
saving
for breakfast
Forgive me
they were delicious
so sweet
and so cold
on 29. October 2024, 20:50 by glum_hippo
Penpa-Fassung: https://tinyurl.com/ibagFreude
on 27. October 2024, 17:27 by wichtel
So, dies ist der Schluss der Wichtelsaison 2023, für die neue Runde läuft ja die Bewerbungsphase (https://forum.logic-masters.de/showthread.php?tid=2221). Vielen Dank an alle TeilnehmerInnen für die tollen Rätsel und an die Wichtelhelfer glum_hippo (Übersetzungen) und ibag (Testlösen)!
