Logic Masters Deutschland e.V.

Point the Way (Arrows/Indexers)

(Published on 23. August 2024, 17:36 by damo_89)

Inspired by juggler's series of indexing puzzles, I have set this with indexing arrows. It's tricky to judge the difficulty of an indexing puzzle. If you get the concept this could collapse quite quickly, but consensus testing opinion was around 3 stars. There is also a 6x6 version which I would rate at 1 star.

  • Normal sudoku rules apply: Place the digits 1 to 9 once each in every row, column and 3x3 box.
  • Arrows: Digits on an arrow sum to the digit in the attached circle.
  • Arrow Indexers: Read from circle to tip, if an arrow has the digits XYZ, then the digit X is in row Y and column Z. For example if an arrow contained the digits 514, then a 5 is in row 1 column 4.
  • ALL cells that can be indexed have exactly one corresponding indexing arrow, apart from the given 6 in the grey square which does not have any corresponding indexing arrow.

Play on Sudokupad


6x6 Example: This has the same rules as the 9x9 version, minus the negative constraint. I.E. It is not necessary that all digits which can be indexed, must be indexed. Play 6x6 version on Sudokupad / See completed 6x6 grid

Solution code: Row 9


Solved by SKORP17, terrible_casserole, kublai, cybers, BirdyChirp, Vodakhan , wang, lmdemasi, pazqo, Megalobrainiac, RobotChicken
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Comments

on 24. August 2024, 14:45 by lmdemasi
A great addition to the indexing series!

Last changed on 24. August 2024, 17:06

on 24. August 2024, 13:32 by Skaev
"ALL cells that can be indexed have exactly one corresponding indexing arrow, apart from the given 6 in the grey square which does not have any corresponding indexing arrow. "

Either I am missing something or this instruction is incorrect. i.e. it is possible to index R2C2 therefore by the rules it must be, however to do so you would have a 4 which would combine with the 6 to make the circle a 10. could you please clarify?

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Damo: if R2C2 were a 4 then it would be possible to index that cell by there being a 422 arrow somewhere in the puzzle. Hence if R2C2 were a 4 then there must be a 422 arrow somewhere in the puzzle. Hope this clarifies matters.

on 23. August 2024, 19:47 by cybers
Very clever and super enjoyable!

Difficulty:3
Rating:N/A
Solved:11 times
Observed:1 times
ID:000JI4

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