Logic Masters Deutschland e.V.

Modulo Yin Yang 2

(Published on 19. August 2024, 07:19 by wuc)

My fourth addition to the modulo series. Since the Modulo Yin Yang Puzzle was most fun to set, I did another one with new constraints. Leave a comment if you liked it.

Standard sudoku rules apply: The digits 1 through 9 appear in every row, column, and box.

Yin Yang: Shade some cells such that all shaded cells are orthogonally connected and all unshaded cells are orthogonally connected and no 2x2 area is fully shaded or unshaded.

Modulo 3 shading: The value of digits on shaded cells count modulo 3, meaning that the value of each digits is its remander when dividing by 3. E.g.: 7 has the value 1.

Region Sum Lines: Box borders divide each blue line into segments with equal SUMS of VALUES.

XV-Dominos: The VALUES of cells separated by an X must sum to 10. The VALUES of cells separated by a V must sum to 5. Not all Xs and Vs are necessarily given (no negative constraint).

Additionally cells separated by an X and a V must be shaded differently.

play on sudokupad

Solution code: Digits of the shaded cells in row 7.

Last changed on on 19. August 2024, 09:23

Solved by cybers, soumyagupta0127, gdc, Piff, Onyx, palpot, Cosinus, Vodakhan , Sinuit, Tompzini, yttrio, johncj, Jagga, irq, dmgciubotaru, MaxSmartable, wenchang, SKORP17, koba1917, jerbear29, elpadrinoIV, atomvic, crustaceous, NeroChaos, lmdemasi, gopher78, Laermans, bielaczek, pasta_al_tonno, littlebluue, Wintermute7, joelth, asii
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Comments

on 25. August 2024, 18:49 by wenchang
Great YinYang! Spoiler alert! https://youtu.be/TKrXSK1rgUE

on 21. August 2024, 21:27 by johncj
Great puzzle. Thank you

on 21. August 2024, 09:14 by yttrio
Very fun follow-up to the first Modulo Yin Yang! Really smooth logic throughout the solve.

on 20. August 2024, 12:24 by Cosinus
YY and Modulo fit together perfectly!

on 19. August 2024, 09:23 by wuc
Corrected the solution code, thanks cybers.

on 19. August 2024, 08:11 by cybers
Great puzzle!! Lots of interesting discoveries one has to make throughout. Thanks for setting this and the rest of the series! (Also, the solution code asks for shaded cells but accepts only the unshaded ones.)

Difficulty:3
Rating:98 %
Solved:33 times
Observed:0 times
ID:000JF1

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