Killocator: Dead or Alive
(Published on 28. February 2024, 10:17 by starwarigami)
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Fill the grid with digits 0-9 so that no digit repeats in any row, column, or 3x3 box.
To enable this, there is a single Schrödinger cell in each row, column and box that contains two digits.
Digits may not repeat in a cage, and each cage sums to a 2 digit total. Cages of the same size must each have a different total.
If a cage enclosing n cells sums to a total "xy" then the digit n appears in row x column y. It is not necessarily the only digit in that cell.
e.g if a 4-cell cage sums to 25, then 4 must appear in R2C5.
Other challenging puzzles you may enjoy:
Solution code: Row 9 (left to right) - 10 digits, no spaces
Comments
on 7. August 2024, 15:38 by Silverstep
intricate start. no step stand out as being a particularly difficult "break-in", it's many small steps building on top of each other.
on 29. July 2024, 12:11 by andreatetta
Is the size of a cage the number of digits it contains or the number of cells it is made of?
Edit: I just finished the puzzle. It is indeed great.
Regarding the question, one can figure out from the example given in the rules that size of a cage means the number of cells it is made of.
on 5. March 2024, 04:47 by Aaronomys
This was so good, I broke it four times! Seriously though, the interactions explored in this puzzle are phenomenal.
on 29. February 2024, 18:12 by samuel1997
Brilliant! It caused me headache though and I have to rest now!
on 29. February 2024, 14:36 by A Mehdi
I thought i broked the puzzle but was able to solve it after rules update...
Very tough and beautiful puzzle !
on 29. February 2024, 10:02 by starwarigami
Updated rules for clarity.
Thanks to @sanabas for pointing out the misleading wording in the description!
on 29. February 2024, 08:51 by sanabas
That was incredible. Very tough to get started, and hard to keep track of possibilities. But after finally getting the first handful of digits, it still flowed really well, and remained reasonably challenging and extremely elegant until the end.
Highly recommend trying this.
