This Tapa puzzle has multiple openings, followed by a long and challenging solve path. It was created by Jakhob and wooferzfg.
Shade some cells so that all shaded cells form one orthogonally connected area and no 2x2 region is entirely shaded. Clues cannot be shaded, and indicate the lengths of the blocks of consecutive shaded cells in the (up to) eight cells surrounding the clue.
Solution code: For each of the marked columns (from left to right), the lengths of the blocks of consecutive shaded cells (from top to bottom)
on 3. April 2024, 14:32 by AnnaTh
Beautiful and challenging! Helps to mark the loose ends with different colours :-)
on 3. March 2024, 12:26 by Statistica
Sehr schön. Hat mehrere Tage Spaß gemacht. Erinnert an das erste und große Tapa hier im Portal mit der ID 000018.
on 3. March 2024, 11:47 by Piatato
Magnificent! Enjoyed it a lot!
on 2. March 2024, 16:37 by Jesper
Epic puzzle, a big undertaking but comes together really nicely
on 28. February 2024, 16:55 by PixelPlucker
Great stuff. Thanks for the giant scoop of vanilla
on 28. February 2024, 05:58 by Agent
Wow, that was insane! I'm pretty sure this is the hardest standard puzzle I've ever solved.
on 27. February 2024, 19:25 by Playmaker6174
What an epic and engaging journey! Very consistent difficulty throughout and it keeps requiring one to think about connectivity logic till the very end, which makes every deduction feel so rewarding after certain stages. I particularly enjoyed working out the opening(s) and near the end x)
(also this reminded me of some painful memories when setting my own 18x18 tapa puzzle xD)
on 27. February 2024, 19:14 by Niverio
Very consistent journey throughout! It felt pretty "similar" through all the 1200 cells one needs to go through. Absolute fun!
on 25. February 2024, 22:45 by KNT
what a marathon! loved it.
on 25. February 2024, 08:14 by Christounet
Awesome ! Easily the hardest pure tapa I have ever solved. Enjoyed every minute of this long marathon, with lots of original tapa/connectivity logic. It was very satifying to see all the parts converge. Thanks :)