The Maze
(Published on 3. February 2024, 09:30 by Twan2797)
Rules:
Place the digits 0-8 once each in every row, column, and 3x3 box.
Draw a Maze in the grid so that the entire path from the entrance to exit is orthogonally connected and the walls are orthogonally connected to at least one border. The borders are considered walls with the exception of the entrance and exit.
No 2x2-region may be completely covered by the path or by walls.
Squares indicate lightswitches. Circles indicate lightbulbs.
Lightswitches: The number in on a lightswitch indicates how many lightbulbs there are directly adjacent to the lightswitch horizontally and vertically. Light switches can only be placed on walls.
Lightbulbs: The lightbulbs have to be determined by the solver and can only be placed inside the maze (not on walls). They can only be directly adjacent to a lightswitch (with one exception being the given lightbulb). No two lightbulbs can be directly adjacent horizontally or vertically. The number in a lightbulb indicates how much light the bulb gives (how many spaces it lights up in total) in a horizontal and/or vertical line. The walls block the light. The entire maze must be illuminated, including the entrance and exit. One space cannot be illuminated by two different lightsources.
An X works as a connector of two places, which both have to be either walls or part of the maze. The two cells have to sum to 10.
Puzzle Link:
Solution code: Column 2, top to bottom (9 digits)
Comments
on 7. February 2024, 16:44 by fopkovic
Wow, this was very very difficult, but satisfying to get it in the end. Thanks for sharing.
on 6. February 2024, 02:04 by Twan2797
Updated CTC rules
on 4. February 2024, 20:07 by gfoot
I had a go, but fairly quickly ran into a contradiction in the upper right corner, so I'm afraid I must have misunderstood the rules.
R1C8 and R1C9 must be empty, and R2C9 is wall as it is a switch. Any bulb that illuminates R1C9 will also illuminate R1C8, and any bulb that illuminates the entry/exit above R1C8 will also illuminate R1C8 itself. The only way one bulb could illuminate all three of those squares (R1C8, R1C9, and the entry/exit square) is with a bulb on R1C8, but that's not allowed as it is not adjacent to a switch. So there must be multiple bulbs there to illuminate those squares, but then R1C8 would be illuminated by more than one bulb, which is also not allowed.
I'm afraid I'm not sure which bit of the rules I have misunderstood.
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Have you considered that a lightbulb may only light up itself and another lightbulb lights up the additional path? Let me know if it's clear what I'm hinting at. "The number in a lightbulb indicates how many spaces it lights up"
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Ah OK so the number actively limits how far it reaches? I had thought it meant the number had to match how far it could see, thanks for clarifying!
on 4. February 2024, 11:42 by Twan2797
Clarified the rules
on 4. February 2024, 11:07 by ridesdragons
just checking, but the borders also count for the 2x2 rule, correct? and do the lightswitches need to be on the path as well (reachable) or do they need to be in the walls (wiring), or does it not matter (wall-ness determined by the solver on a case-by-case basis)? edit: oh shoot, I didn't see the 0-8 rule. surely lightbulbs can't be inside walls, can they? -surely-.
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Your assumptions are correct. Outside borders count as walls for the 2*2 rule an lightbulbs can't be on walls, light switches can't be on paths, I will clarify the rules.
on 3. February 2024, 22:12 by Twan2797
Clarified the rules
