Logic Masters Deutschland e.V.

Prime X-Sums

(Published on 27. August 2023, 15:34 by Florian Wortmann)


Normal sudoku rules apply.

X-Sums
A clue outside the grid is the sum of the first X cells in the corresponding row/column, where X is the digit in the cell nearest to the clue.

Just as for the given sums, the sum for a ?-clue is prime, but must be determined by the solver.


Link: CTC-App




Solution code: row 3

Last changed on on 28. August 2023, 13:42

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Comments

on 30. August 2023, 07:16 by cmb
nice flow.

on 29. August 2023, 01:10 by nseydel
If we were to accept 1 as a prime (divided only by 1 and itself), prime factorisation would be not unique (e.g. 12 = 2^2 * 3 or 1 * 2^2 * 3 or 1^2 * 2^2 * 3 ...). That would be terrible for any mathematical proof. Primes are the units of numbers, any integer can uniquely be shown as a product of primes (only except for the order of factors). So amongst mathematicians, 1 is NEVER regarded a prime. Remember: a prime is a number with exactly two divisors, but 1 has only a single divisor: 1. That being said, it can never hurt to mention '1 is not a prime' in the rules of a puzzle featuring primes.

on 28. August 2023, 13:42 by Florian Wortmann
formatting

on 28. August 2023, 13:33 by Florian Wortmann
added image of prime numbers

Last changed on 28. August 2023, 20:12

on 28. August 2023, 01:35 by Snaques
It's definitely a 'me' problem, but it might be a nice hint to remind that 1 is not actually a prime number.

I've heard it debated both ways and at least I couldn't find a solution until I confirmed that it is indeed not a prime.

Otherwise very enjoyable puzzle.

--
Thank you for the kind comment. I was not aware that it might be unclear whether 1 is prime or not.

The definition I know is that a number is prime when it has exactly two "real divisors" (not sure if that is the proper english term).

I now added an image with all prime numbers 1-50 to avoid any further confusion.

Snaques: Been a while since I was at school, so I thought a number is a prime if it is only divisible by 1 and the number itself. Internet seems to agree with you, so I just needed a refresher.;)

Difficulty:2
Rating:91 %
Solved:65 times
Observed:9 times
ID:000EYD

Variant combination Online solving tool

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Solution code:

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