This hopefully will be a fun little ruleset -- and not too difficult. (I can imagine much harder versions of this ruleset -- maybe even without any sandwich totals given? (thanks bigger!) Or perhaps no circled cells allowed? Or double digit circled clues? If any of you decide to make one, please let me know so I can solve it for you!) Have fun!
The Rules:
The Puzzle:
Solution code: Row 2
on 7. June 2023, 03:27 by Allagem
Bizarre but beautiful logic. Loved it!
on 12. May 2023, 14:02 by Bankey
An enjoyable ride, once you wrap your head around the unusual ruleset. Thanks for setting and sharing, @ RockyRoer:)
on 11. April 2023, 11:16 by argl
Brilliant; a very smooth but at the same time non-trivial solve once one figures out the implications of the constraint. Thank you for elaborating the rules for another user in the comments, I needed that as well.
on 6. April 2023, 13:03 by RockyRoer
Added link to bigger's puzzle with a similar rule set.
on 6. April 2023, 12:40 by Snookerfan
Great and smooth puzzle! Thank you
on 6. April 2023, 08:30 by ScatterBrain
I gave up on this a couple of days ago, then tried and succeeded on bigger's All Sandwich Counts (https://logic-masters.de/Raetselportal/Raetsel/zeigen.php?id=000DIL) which was inspired by this one.
Then I came back to this one and figured it out! Thanks RockyRoer.
on 5. April 2023, 18:45 by RockyRoer
Edited rules per suggestion in comment
on 5. April 2023, 14:20 by Franjo
Wonderful puzzle - as always. One suggestion you might add to the rules:“ If a CIRCLED cell is simultaneously…“
on 5. April 2023, 10:09 by Piatato
Fun puzzle! Silky smooth resolution in the end :)
on 4. April 2023, 23:14 by ScatterBrain
Not sure I understand, a circled cell is the sum of the sandwiched cells in its row and column?
Reply: no, a circled cell indicates how many cells in that row and column combined are in sandwiches. So, if r1c5 is a six, then there must be a combined total of 6 digits in sandwiches in row 1 and column 5.
If r4c6 is a six, then row 4 might have three cells sandwiched between the 1 and 9 and column 6 also have three (combining to six) but if r4c6 is in both, then it can only be counted once so you would need one more cell in either the row or column.
Difficulty: | |
Rating: | 96 % |
Solved: | 47 times |
Observed: | 9 times |
ID: | 000DIB |