Logic Masters Deutschland e.V.

Squeeze

(Published on 6. March 2023, 23:36 by JamesCullum)

Squeeze is the 6th in a series of sudokus that use an adapted arrow sudoku ruleset, namely that digits on an arrow must sum to either double or half of the digit within that arrows circle cell.

It has made for some fun puzzles so far, but please join me on my quest to master this ruleset!

Rules:

1. Normal sudoku rules apply.

2. The value of an arrow bulb is either half or double the digit in the bulb, and this value is also the sum of the digits on the arrow.

3. Digits outside the grid show the sum of the values sandwiched between the 1 and the 9 in the column or row.

4. In cages, values must sum to the small clue in the top left corner. Digits cannot repeat within a cage.

5. Anti King, cells a king move apart in chess cannot contain the same digit.

Puzzle Links:

Sudokupad

F-Puzzles

I hope you enjoy the puzzle.

Solution code: Row 1 and 9, no spaces.

Last changed on on 30. August 2023, 16:38

Solved by MonsieurTRISTE, OutOfMyMindBRB, bigger, jalebc, Bjd, bansalsaab, msbjowmx1, Entropywins, FrogMatic, aaronjones5151, novarielet, Bankey, gadwin, quintintin, packageofbeef, PippoForte, pandiani42, flipout, Paletron, Gotroch, only1evenprime, juddimal, ophelias
Full list

Comments

on 14. May 2024, 03:17 by only1evenprime
Loved the flow of this puzzle, everything worked well together.

on 11. August 2023, 13:46 by Bankey
Fun puzzle. Thanks, @ JamesCullum :).

on 8. March 2023, 12:47 by FrogMatic
Different concept from the last, I love the cage busting totals from some of the previous in this series.

on 7. March 2023, 16:37 by bansalsaab
Damn, i forgot to use the kings rule and was stuck for a while.

Last changed on 7. March 2023, 00:18

on 7. March 2023, 00:05 by MonsieurTRISTE
For the second rule, do you mean the value of a circle is equal to the sum of digits on the connceting arrow, which is also 2 or 0.5 times the digit in the circle?

EDIT: Yes, so if the circle is a 4, then the arrow digits sum to either 2 or 8.

Difficulty:4
Rating:98 %
Solved:23 times
Observed:8 times
ID:000D6X

Enter solution

Solution code:

Login