Solution code: Row 4 followed by column 3 with the following encoding:
X - unshaded cell without loop
S - shaded cell without loop
I - unshaded cell with straight loop segment
SI - shaded cell with straight loop segment
L - unshaded cell with turn of the loop
SL - shaded cell with turn of the loop
on 6. October 2023, 17:39 by The Book Wyrm
Very good puzzle. Took me a while to fully understand the implications of the rules, but once I did it flowed very smoothly, very some neat logic, that combined both genres well.
on 16. April 2023, 18:55 by wooferzfg
Fun and smooth!
on 12. January 2023, 19:29 by StephenR
Thanks, interesting ruleset which did indeed take me a while to understand. But I may not be the best judge of difficulty as it took me four attempts to enter the solution code correctly.
on 2. January 2023, 07:52 by dangernoodle
It was a hard one for me but that's because I'm not super familiar with the ruleset...
on 28. December 2022, 15:33 by Samish
Wonderful puzzle already! Looking forward to trying the biggie
on 22. December 2022, 08:51 by Christounet
Ok, I can see a very hard #2 coming our way very soon, I think...
Thanks for this appetizer !
on 22. December 2022, 08:41 by Mark Sweep
Very nice and smooth introduction! This felt easy, but I can see this getting quite tricky.
on 21. December 2022, 19:59 by Niverio
Lovely! Afraid and anticipating of what might be coming next...
on 21. December 2022, 19:38 by KNT
very pleasant solve. both excited and scared for #2
on 21. December 2022, 18:14 by Agent
Very fun and approachable hybrid!
on 21. December 2022, 18:11 by Dermerlin
I am looking at the example and don't understand the last rule. What about the numbers in a field? the 4 is seeing 5 fields and one segment. How can it be the sum of the length of all segments in the direction of the arrow? The 4 is not the only number i don't understand in the example. the black 1 is a mystery as well (and more numbers are)
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Thanks for the question. As you can see in the rule, the count is for "the number of times the loop crosses a cell border in the given direction". This means you count the number of times the green loop intersects the thin black grid lines. So for the black "1", you can see that the loop intersect the grid line between R6C7 and R7C7 but no other grid lines in C7 beneath the clue, hence the 1. Hope this helps! /Magnus
Thx for explanation. I think i got the ruleset now. But as i am not too familiar with Yin Yang i still failed at my first try. Not ready to give up yet :)
on 21. December 2022, 16:55 by polar
Charming puzzle - very much looking forward to #2 :)
on 21. December 2022, 16:51 by ONeill
A great combination of rules, and a pleasant introduction, thanks!
on 21. December 2022, 15:55 by MagnusJosefsson
This is an introductory puzzle to this new ruleset that I am quickly getting quite fond of. I originally created it as an example for a more challenging puzzle, but in my opinion it turned out quite nice on its own.
Difficulty should be two stars, though perhaps for some solvers there may be steps that seem more challenging (due to unfamiliarity with the ruleset).