Rules
Latin Square: Place the digits 1-7 once in each row and column.
Nurikabe: Shade some cells in the grid such that all shaded cells are orthogonally connected, and no 2x2 area is completely shaded. Unshaded cells form islands, which are referenced by JSS clues. Digits cannot repeat on an island.
Arrow: Digits on an arrow must sum to the number in the attached circle. Digits may repeat on an arrow where allowed by other rules.
Japanese Sums: Outside the grid, digits may freely repeat and may be higher than 7, but must obey Arrow rules. The values outside the grid give the sum of each contiguous run of unshaded (island) cells in that row or column. Either all or no clues are given for that row or column. “?” is a stand in for any digit 0-9, but for a double digit number, the first digit may not be 0.
Penpa Link
I have included a hint for the opening below, highlight to see it:
What would happen in column 7 if r1c7 was shaded?
Solution code: Row 1, row 7
on 27. September 2023, 05:16 by zzw
Awesome puzzle! Break-in was a bit tough until I considered all the rules (hehe), after that it was quite smooth with lots of interesting deductions. Excited to try the big one!
on 9. May 2023, 10:56 by Christounet
Original rule and a nice flow after the break-in, which was not that hard if you're somewhat familiar with J-Sums shading. Thanks !
on 14. December 2022, 00:39 by Xendari
Edited german translation & fixed ruleset
on 13. December 2022, 18:59 by KNT
Great to see setters branch out into Japanese sums, they're always so fun to solve. More please :)
on 13. December 2022, 18:27 by StefanSch
Der vorgeschlagene Einstieg ist ohne Hinweise nur schwer zu finden. Danach geht es flüssig durch.
@Xendari: Better translation "Lateinisches Quadrat" instead of "Lateinischer Platz"
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vielen Dank für Ihr Feedback und die Übersetzung :)
on 13. December 2022, 16:02 by ONeill
Fun ruleset, thanks :)
Difficulty: | |
Rating: | 94 % |
Solved: | 17 times |
Observed: | 6 times |
ID: | 000CB2 |