Logic Masters Deutschland e.V.

CtC 500k Tribute

(Published on 30. August 2022, 05:56 by apiyo)

This is a tribute to CtC's recent milestone of 500,000 subscribers. Good Grief!

It might look a bit gimmicky, and has a lot of rules, but I was pleased with how it turned out. I like the solve path, which has a tricky deduction or two in each phase of the solve. I didn't want the yellow line to look like a face... but the nose was a necessary compromise! I hope you have fun!

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Normal Sudoku rules apply.

Neighbouring digits along the yellow Dutch Whisper line must differ by at least 4.

Digits along the red line are to be read as four 2-digit numbers running around the triangle. These four numbers add to 100. It's for the solver to deduce the ones digits/tens digits parity.

The letter K between cells means that one of the digits is a factor of the other.

Letters within cells represent different numbers. eg, the two C's are the same digit, while B cannot equal C.

Digits joined by a V or X sum to 5 or 10, respectively.

Digits joined by a white dot are consecutive.

Digits on a grey circle are odd.

(There are no negative constraints.)

If you would like to see a solve video for this, feel free to drop me a line on discord and I'll put something together.

Enjoy!

Solve at f-puzzles

Solve at CtC

Solution code: Row 7 followed by Column 8 (18 Digits)


Solved by lsw770770, Myreque, Chelo, nunc, SKORP17, Notlob, AKernel, bansalsaab, SirWoezel, mcc, peacherwu2, Briks, MONICHOO, PippoForte
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Comments

on 31. August 2022, 15:58 by SirWoezel
Fun puzzle, and I agree with 4 stars.

Last changed on 31. August 2022, 06:07

on 30. August 2022, 15:42 by Chelo
What a challenge!... WOW!.. Thank you @apiyo for this fantastic tribute, it was very hard for me but I've had lots of fun in solving it!.. Quite tricky, but a fully logical solving path.

// Thanks Chelo! Really glad you enjoyed, and thanks for the feedback. I agree it was hard. Always difficult to assess difficulty for the purpose of this site, given the high standard. But against my own solving ability I would have ranked this 4.

Difficulty:4
Rating:91 %
Solved:14 times
Observed:7 times
ID:000B0L

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