Logic Masters Deutschland e.V.

Living up to my name

(Published on 29. July 2022, 08:17 by Fool on Hill)

Puzzle rules

Normal Sudoku rules apply.

Orthogonally adjacent cells may not be consecutive. Cells separated by a knight's move or a king's move in chess must be different. A black dot separates cells with a ratio 1:2. Not all dots are given.

Here is the Cracking the Cryptic link: Living up to my name

Here is a Penpa+ link: Living up to my name

Solution code: Row 7 of grid

Last changed on on 11. September 2022, 17:03

Solved by avahales, henter, Dentones, Isa, jalebc, Ocean, Gryllulus, SKORP17, Tilberg, kkli, slowbiex, jguer, bansalsaab, mattnburris, Danica, ___, achim-t, Kigor, Greg, sayuri17, Arcadiotl, jhuijts, AvonD, ... drblaubaer, AN_not_IO, wreo, KatiBru, Carpet11, Carolin, jadezki, MB_Cyclist, morgannamodeaura, damasosos92, Krokant, MaxSmartable, flipout, ClarityC, Koba, Jdt112, luuu, annnz, cbrown92
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Comments

on 5. August 2022, 02:37 by PepperWood
Very satisfying once the initial "aha!" kicked in. Love going from a totally blank grid to suddenly everything making sense.

on 30. July 2022, 19:34 by Fool on Hill
@farodin64 It can be done without using the box 3 dot. I've done it myself, but had to do long chain eliminations. The box 3 dot helps neatly with a solve path I found. But if there is a good solve without the box 3 dot, kudos for finding it. The secret Yawnus knows makes a huge difference, but that has to be shown first (in my way of thinking about a solve) and that is not trivial.

Last changed on 14. August 2022, 23:22

on 30. July 2022, 14:50 by farodin64
Nice puzzle, thanks for the fun! Btw my solve was w/o using the black dot in box 3. May be it can shorten the flow somewhere.

Just getting used to the fact that I can reply to comments by editing them. I couldn't find a nice solve-path with just three dots, though I did find solutions without either c2 or c7 (so two three-dot puzzles). If there is a clean solve without one of the dots, then well done for finding it. The way I do it the c7 dot has a part to play.

Thanks so much also for the feedback - this was my first puzzle on LMD, and I am learning fast (though perhaps not quite quickly enough)

Last changed on 30. July 2022, 12:25

on 30. July 2022, 12:23 by Fool on Hill
@Yawnus. Thanks for the information. I have been discovering for myself how powerful these constraints are, and have noticed some things. I think I will move on to disambiguating non-consecutive, or non-consecutive anti-knight grids as there is some logic I wanted to showcase which was constrained away when I explored the Miracle options. I have put up another Miracle puzzle which disambiguates rather differently. The Kropki method I want and the XV method in the other (Dead Roman Miracle) would both work for non-consecutive puzzles, but I want constraints to avoid (if possible) given digits. I will keep looking. Meanwhile this was fun to explore on holiday.

on 30. July 2022, 10:39 by Yawnus
This set of constraints, popularized by Mitchell Lee's Miracle Sudoku, is really powerful. There are unique solutions for two given digits, two Kropki dots, a single arrow or killer cage, for example. Most of those are very difficult for humans to solve, unless you know the secret of this ruleset (in a hidden comment).

on 30. July 2022, 01:08 by Frans Wentholt
Very nice! Not as hard as I thought it would be.

on 29. July 2022, 20:54 by Arcadiotl
I really enjoyed it, thanks a lot!

on 29. July 2022, 15:44 by slowbiex
loved it from beginning to end - even if it took me way over an hour!

on 29. July 2022, 14:57 by Tilberg
Nice miracle variant. Thank you!

on 29. July 2022, 10:20 by Fool on Hill
I think this solves with only three dots - either of the singles can be deleted. But that required lots of bifurcation. I think there is a decent human solve possible with the extra dot.

Last changed on 29. July 2022, 19:54

on 29. July 2022, 08:49 by Fool on Hill
Newbie improving the formatting

Difficulty:3
Rating:93 %
Solved:79 times
Observed:8 times
ID:000AMG

Variant combination

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Solution code:

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