Squares of parity
(Published on 16. June 2022, 20:38 by PetLov)
Normal sudoku rules apply.
A digit in a square must equal the number of orthogonally adjacent odd or even digits.
All possible squares are given.
A digit in a circle is the sum of two or more orthogonally adjacent digits.
A digit in a square must equal the number of orthogonally adjacent odd or even digits.
All possible squares are given.
A digit in a circle is the sum of two or more orthogonally adjacent digits.
Solution code: Row 4 and column 4
Last changed on on 17. June 2022, 06:56
Solved by cmb, SirWoezel, Isa, PippoForte, Richard, Krokant, Gryllulus, misko, KlausRG, Rollo, faisalaak
Comments
Last changed on 10. January 2023, 18:23
on 10. January 2023, 13:35 by Rollo
Wonderful! Richard's inspiration for his puzzle CDK. Unbedingt machen!
on 21. December 2022, 16:09 by Krokant
Fantastic puzzle. Never got stuck too long, it went quite smoothly. Had a lot of fun solving it. :)
on 19. July 2022, 22:49 by Richard
Wow, what a tight solve path! Challenging untill the very last digit.
Very nice interactions between the different meanings of the symbols.
This puzzle deserves far more solves!
on 16. June 2022, 22:56 by cmb
Neat.
Espacially when the two circles resolved the double deadly pattern in the end.
