Biagonal Bichael (Chaos Construction)
(Published on 29. May 2022, 17:32 by purpl)
Rules:
Normal Chaos Construction rules apply. Place one of each digit 1-9 in every row, column, and region, but the regions must be determined by the solver. That is, divide the grid into 9 orthogonally connected groups of 9 cells.
Clues outside the grid give the sum of the digits on the indicated diagonal, digits may repeat along these diagonals ;)
Circles give the number of distinct regions in a 3x3 box centered at that circle (if they are on an edge they refer to the cells of that 3x3 box in the grid). Squares either give the number of cells in the row or the number of cells in the column of their region that the square is also in, these cells may be disconnected or contiguous segments. Not all circles/squares are given.
Links:
If you enjoyed this puzzle, consider leaving a rating and/or comment. Better yet recommend it to your fellow solvers if you liked it that much! I hope you do so for all the puzzles you enjoy ;)
Also check out the puzzles/setters I linked in the first paragraph if you haven't already.
Solution code: For the region containing r2c2, record the digits of this region as they appear left to right, top to bottom. Do the same for the region containing r5c3. 18 digits in total, no spaces.
Comments
on 10. June 2022, 10:07 by Christounet
Very nice puzzle ! I always wondered if a chaos construction puzzle would be possible with such a diagonal filled that way (don't want to spoil anything even if it is kind of obvious how this diagonal is filled). Now, thanks to you, I know it is possible. Very well done !!
on 5. June 2022, 20:24 by Snookerfan
Great puzzle! Many easy digits from the start, but then the hard journey begins, super fun!
on 31. May 2022, 20:42 by wenchang
very easy for the first few digits. Then very hard.
https://youtu.be/CA56NYiB5kw
on 31. May 2022, 15:02 by MagnusJosefsson
Great puzzle, very fun and challenging!
on 31. May 2022, 02:29 by peacherwu2
The generous breakins gives illusions this is gonna be easy, but I was so wrong!
on 31. May 2022, 00:44 by wenchang
It is very very hard. It took me 1.5 hours. Time is flying when solving it.
on 30. May 2022, 22:40 by Jay Dyer
Great puzzle! Kept me on my toes until the very end.
on 30. May 2022, 15:39 by robals
Wow, what an afternoon. Easy start, but I got stuck mid solve. Very fun. For me harder than 4 stars :D
on 30. May 2022, 05:19 by Agent
Very nice! The mid-solve was surprisingly resilient after these very generous little killers.
on 29. May 2022, 22:51 by Jesper
A lot of fun!
on 29. May 2022, 22:04 by LittleBallOfPurr
This puzzle felt so rewarding throughout, lots of lovely little deduction and rewards.
Extremely challenging to break in with a first digit, as I'm sure many will notice.
Thanks so much, for such a delightful piece of work!
on 29. May 2022, 21:45 by KNT
this puzzle is as good as the title is terrible, which is to say a very good puzzle
on 29. May 2022, 21:42 by purpl
This is proving to be more difficult than indicated by testing
on 29. May 2022, 21:41 by Dandelo
Very nice, and quite hard. And it is very easy to make mistakes... For me it felt like more than 3/5.
The rules are clear now. "either" is sufficient, but writing "the number of" twice is also enough.
I really started with the wrong rules.
This row-or-column-problem appears frequently and even if the wording is correct, it sometimes causes misunderstandings.
on 29. May 2022, 20:35 by kolot
Pretty simple start and some challenging and interesting deductions afterwards which were fun to figure out.
on 29. May 2022, 19:43 by Dandelo
There would be 5 cells which have the property to be in the same row or column.
But now it's clear, I think. Maybe a picture would be the easiest way?
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purpl/Memeristor: Oh! I now understand what you mean. Sorry about that, I think the word either does clear that up. If there is further confusion I will add a picture.
on 29. May 2022, 19:27 by purpl
Adjusted the rules for clarity on the points below.
on 29. May 2022, 19:13 by Dandelo
If there are 2 cells in the same row and 3 cells in the same column, would a square contain 5? Or could it contain either 2 or 3?
I think the rules could be read in both ways.
on 29. May 2022, 18:43 by SKORP17
es gibt 3 Circle am Rand , die nicht das Centrum einer 3*3 Box sein können, was enthalten die denn?
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purpl/Memeristor: Well they can be the center of a 3x3 box, its just that 3 of the cells happen to be outside the grid, so clearly only the 2x3 (3x2) cells within the grid would be relevant to the solve.
on 29. May 2022, 17:32 by purpl
Typo in the title *facepalm*
