Logic Masters Deutschland e.V.

Queen's Gambit

(Published on 14. January 2022, 15:58 by Will Power)

Normal Sudoku rules apply. For numbers 1, 2, 3 and 4, the same number cannot be a chess QUEEN's move apart (ie: ALL diagonals can have a maximum of one each of numbers 1, 2, 3 and 4). Numbers with an X between them sum to 10. Numbers with a V between them sum to 5. Not all possible X's and V's are shown.

F-Puzzles

Solution code: Row 1 and column 5, no spaces.


Solved by Gullie, Steven R, SKORP17, Greg, BlackApolloX, jalebc, fpac, valdal, gige, XhcnoirX, Realshaggy, samuella, chippers, wjdrumm, Calvinball, skywalker, meowzzz, weiken, Raistlen, mathpesto, ... ludvigr04, Gosciola19, Sileem, pepe74287, mattnburris, Numpus, Thomster, cascadeshiker, Nylimb, 333sudoku333, timww572, LachyDachy, Ahrun, naggy, k2u5as, augsod, Csmith928, asii, koiking, Cezarr
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Comments

on 26. November 2023, 19:39 by cascadeshiker
This was a fun puzzle. Took me a while to figure out how to attack it though.

on 14. February 2023, 18:33 by Hydalin
Easy one but very nice set-up. Really liked it, definitely a one star for me

on 12. February 2022, 17:43 by haligonian
Oh, this was fun! For me, about a 2 star. But approachable once I remembered to keep checking that diagonal constraint ;)

on 16. January 2022, 08:07 by Will Power
Bruno's original understanding was correct. There is a maximum of one each 1, 2, 3, and 4 on ALL diagonals. None of the numbers 1, 2, 3, or 4 can be a chess queen's move apart.

on 15. January 2022, 22:08 by Bruno
I didn't understand the rules well, I thought it was all the numbers 1,2,3,4 that couldn't be a chess queen's move apart. But it was only in the 2 diagonals ;)

on 14. January 2022, 20:32 by Shearing
Clever little puzzle. 2-star difficulty for me. Thank you.

Difficulty:1
Rating:85 %
Solved:212 times
Observed:7 times
ID:0008T7

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