Alternating Universe
(Published on 22. October 2021, 02:32 by BellBear)
In my first ever published puzzle I used alternating sums to disambiguate the solution without giving too much away early on. Here the interaction of alternating sums and arrows are the main idea of the puzzle.
Rules
- Normal arrow sudoku rules apply (normal sudoku rules apply and numbers on an arrow sum up to the number in the attached circle).
- On the blue line the outer digits sum to the central digit.
- Numbers outside the grid give the alternating sum of that row/column. The alternating sum is calculated by alternately adding and subtracting numbers (e.g. if you have a row of 873 614 529 - in that order - ist alternating sum is 8-7+3-6+1-4+5-2+9 = 7).
- The numbers within cages - read from left to right or from top to bottom - are divisible by the clue in the top left corner (for dividibility rules look below the puzzle). Note: it's not about the sum of the digits in the cage but just the number read as a decimal number in this cage.
Link to this puzzle in F-Puzzles
Link to this puzzle in CTC app
Divisibility rules
- A number is divisible by 3 if its digital sum (=sum of all digits) is divisible by 3.
- A number is divisible by 11 if its alternating sum is divisible by 11.
Solution code: Row 1 followed by column 6 (18 digits, no spaces)
Last changed on on 10. January 2022, 15:11
Solved by SKORP17, purpl
Comments
Last changed on 10. January 2022, 15:12on 10. January 2022, 15:11 by BellBear
After a discussion with purpl I decided to modify the rules descriptions a little bit.
on 29. October 2021, 17:44 by uvo_mod
Labels angepasst.
on 23. October 2021, 23:34 by BellBear
I changed the solution code description.
on 23. October 2021, 21:52 by BellBear
Just some html stuff
on 23. October 2021, 21:49 by BellBear
Lösungscode angepasst