Logic Masters Deutschland e.V.

Not Between Sudoku

(Published on 29. May 2021, 04:07 by stephane.bura)

Normal Sudoku rules apply.

Circled digits at the ends of a line must be different.
Digits on a line must not be between the two ends, can't be equal to the ends and they must all be different.
The ends and the digits on the line add up to the same number.
All the lines sum to a different total, except for the dotted lines which share the same sum.

For instance, r3c1 + r2c2 = r1c1 + r2c1, all these cells are different (obviously in this case), r1c1 and r2c1 are not between r3c1 and r2c2, and this sum is unique in this grid.

Enjoy!

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Solution code: Column 2, column 3

Last changed on on 30. May 2021, 10:38

Solved by Jesper, marcmees, MagnusJosefsson, henrypijames, polar, Zombie Hunter, SirWoezel, Mody, Arashdeep Singh, abed hawila, Yohann, bolado
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Comments

Last changed on 24. September 2021, 09:34

on 24. September 2021, 00:07 by abed hawila
Very nice, I got stuck for a while cause I forget the different total rule, after that the solve was smooth and interesting.

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Thanks abed :)

on 1. June 2021, 10:41 by SirWoezel
Loved it!

on 31. May 2021, 16:29 by stephane.bura
Thanks Zombie Hunter and polar :)

on 31. May 2021, 05:28 by Zombie Hunter
Great rule set.

on 31. May 2021, 00:42 by polar
Stared at it for a little while before re-reading the rules and noticing all numbers on the line have to be unique! Thanks for another lovely puzzle :)

on 30. May 2021, 10:38 by stephane.bura
Added example

Last changed on 30. May 2021, 10:24

on 30. May 2021, 09:53 by henrypijames
Does the sum of a line include the two ends in circles?
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No. r3c1 + r2c2 = r1c1 + r2c1 and that's the value we're considering.
Although, if you counted them, it would still work regarding uniqueness :)

on 30. May 2021, 02:07 by stephane.bura
Changed the difficulty rating and title.
Thanks marcmees and MagnusJosefsson :)

on 30. May 2021, 01:05 by MagnusJosefsson
Very nice and original!

Last changed on 30. May 2021, 00:18

on 30. May 2021, 00:17 by marcmees
an other stephane reverse thinking beauty. thanks. (4*)

Difficulty:4
Rating:98 %
Solved:12 times
Observed:7 times
ID:0006GX

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