Gravity Sudoku #2
(Published on 14. May 2021, 17:30 by Cane_Puzzles)
This is the second puzzle I constructed with this variant I came up with. You can find the first puzzle
here.
Rules:
1) Standard Sudoku rules apply:
Place the digits 1-9 into each cell of the grid. None of the rows, columns or boldly outlined 3x3 boxes contain repeated digits.
2) Gravity Sudoku rules apply:
The number at the corner of a cage is the sum of the digits that are at most x orthogonal moves away from the cell with the cage - including the digit in the cage - where x is the digit in the cage. (The gravitational effect zone of a cage (the digits it sums) depends on its mass. (the digit in it))
Some clues in this puzzle have inequality signs. This tells that the sum is strictly greater than or less than the given sum.
An example that explains the rule can be found below.
Example: (related to the image above)
Let's say that the green cell contains the digit x and the cage in the green cell gives the sum y.
If x=1, y=Green+Red
If x=2, y=Green+Red+Blue
If x=3, y=Green+Red+Blue+Yellow
If x=4, y=Green+Red+Blue+Yellow+Grey
...
This is the puzzle:
You can try the puzzle
here. As usual, all comments and ratings are always welcome.
I am not a native German speaker, I just use the translations of Google Translate. Therefore, corrections on the German text are highly appreciated.
Solution code: Row 5 followed by Column 8 (18 digits with no spaces)
Last changed on on 10. August 2021, 06:17
Solved by polar, henrypijames, SKORP17, morgannamodeaura, HakanE
Comments
on 10. August 2021, 06:17 by Cane_Puzzles
Added tags
Last changed on 28. May 2021, 07:24on 16. May 2021, 15:34 by henrypijames
Honestly, I find this one less enjoyable than the first one. The novelty wore off a bit, and there's no new logic here, only more laborious calculations (brought on by the inequalities), which I don't like especially when it's just for its own sake.
-Thank you for your comment. In my opinion, the inequalities didn't make the puzzle less enjoyable but it is good to know other solvers' points of view.