Fünfter Pfeilchenstrauß, "Quer Beet"
(Published on 8. December 2020, 16:37 by glum_hippo)
Arrows or Squarrows - Disjoint Group edition!
F-puzzles link.
CtC App link
The usual Sudoku rules apply, i.e., in each row, column, and 3x3 box there must be exactly one each of the digits 1-9.
Disjoint groups: No digit may occupy the same position relative to two different boxes. So for example the middle digits in all 9 boxes (R2C2,R5C5,R5C8,R8C8 etc) must be distinct, as must the top left corners, the right edge cells, etc.
Arrows or Squarrows: The digits along an arrow sum either to the number in the circle (x) or to the square of that number (x times x). The circled digit does not contribute to its own sum. If two arrows emerge from the same circle, their sums are treated separately, not added together, and one could be a square and the other a sum.
Please note that the arrowhead in R5C8 originates in the circle in R2C8, and not in R4C9. The latter is the origin of the arrow than concludes at R2C7!
The other puzzles in this series:
Solution code: The 4th column, then the 9th row (18 digits total)
Comments
on 6. May 2023, 17:29 by glum_hippo
CtC link added
on 15. February 2022, 12:57 by Vebby
Awesome series! Each one was a joy to solve.
—— Thanks a lot, Vebby. I hope to continue this series someday
on 17. December 2021, 17:49 by Realshaggy
Der Klassiker: Regeln nicht mit ausgedruckt. Ohne Disjoint Groups geht hier wirklich sehr wenig.
on 8. December 2020, 22:04 by karen_birgitta
Is there an arrow from r4c9 to r5c8? I suppose not, but just to be sure...
[glum_hippo]: No, that arrowhead in R5C8 extends from R2C8 through the circle in R4C9, and the circle in R4C9 is the origin for the arrow that extends to the right and bends through R3C6 and R2C7
