Logic Masters Deutschland e.V.

This is a two part puzzle. The first part is a sort of jigsaw, where the foundation is laid for the solve. The second part is using lunchbox clues (as created by the great Undar_Beyond) to put numbers in the grid. The first part is easier than the second part, but neither part is too challenging.

A 'corner' in the text below, is a set of 3 orthogonally connected cells not in a line. One of:

Ruleset:

• Standard: Normal sudoku rules apply.
• Diagonal: Each of the long, marked diagonals must contain all of 1-9.
• Lunchbox: Cages in the grid are 1 cell wide snakes. The number in the corner of the cage denotes the sum of the digits "sandwiched" between and not including the highest and lowest digit in the cage. Digits cannot repeat in cages.
• Jigsaw: Place 9 corners containing 3 even digits and an additional 9 corners containing 3 odd digits in the white region of the grid. They cannot overlap.
• Jigsaw: Place 9 corners containing 2 odd and 1 even digit in the highlighted red region of the grid. They cannot overlap.

Link to puzzle in the Fox editor: PUZZLE

Previous version may have been unclear: Begin with the jigsaw puzzle to establish parity across the grid. You have 9 pieces with all even numbers and 9 pieces with all odd numbers. These 18 pieces can only be placed in the white region. And you have 9 pieces with 2 odd an 1 even number - these pieces can only be placed in the red region. Every (27) piece in the puzzle is corner-shaped. Then you place the numbers using 4 cages: a 6 cage of length 9, a 12 cage of length 8, an 11 cage of length 8 and a 25 cage of length 9.
Hints below image. NOTE: The entry to this puzzle is identical to the first puzzle, I ever posted here. The second part however is very different. I took that early puzzle down - it had the rules in a bad quality jpeg (and thusly couldn't be translated), no link to online solving and wasn't printer friendly. As a consequence very few people bothered to solve it - the few that did seemed to like it though. So I decided to reinvent it in a new form.
The people who already solved the earlier version of this are: Julianl, ManuH, marcmees, ch1983, Ours brun, skywalker, zorant, bob, sf2l, NikolaZ
Hint:

The diagonals are extremely important when determining parity, and the resulting parity grid will be symmetric around both long diagonals.

Have a nice day :)