Logic Masters Deutschland e.V.

Parity Party XIII, "Power Hour"

(Published on 30. October 2020, 14:09 by glum_hippo)

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Parity Party XIII

Three primes, two cubes, six squares!

Normal Sudoku rules apply. No digit may repeat in a row, column, or box.

Special rules of Parity Party: A number at the edge of the grid indicates the sum of cells encountered when moving through the grid from that vantage point, UP TO AND INCLUDING the first odd or first even digit. For example, a 15 at the end of a diagonal could indicate something like 7-8, 8-7, 1-3-5-6 or 2-6-4-3 (among others) when reading from that vantage point... and because digits on a diagonal can repeat, 1-3-3-3-4 or 2-4-2-2-7 are also possible; but not 1-2-3-4-5 or 2-6-3-4 etc. That is, the parity of the farthest digit must deviate from that of all the others.

Please note: Unlike in 'little killer' puzzles, you're not necessarily seeing the sum of all digits in the diagonal.

Note: If the clue is less than 10, it might simply indicate the value of the first cell. That is to say, you could be adding up zero odd and one even number, or vice versa.

Solution code: The 3rd and 7th rows (18 digits)

Last changed on on 14. September 2021, 16:51

Solved by Realshaggy, LongOrteil, cdwg2000, SirWoezel, moss, Alexander Rappa, Jesper, Sktx, Debrutsid, mark.ablov, PixelPlucker, NikolaZ, Ours brun, Statistica, zorant, ffricke, MagnusJosefsson, marcmees, sandmoppe, Vebby, ibag, ManuH, Sewerin
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Comments

on 17. March 2021, 21:35 by ffricke
Es hat gedauert, bis ich die ersten Zahlen platzieren konnte und dann hakte es noch eine Weile, aber dann ging es plötzlich flüssig. Wunderschönes Rätsel.

Last changed on 5. November 2020, 17:43

on 1. November 2020, 02:40 by glum_hippo
Thank you for your kind words, LongOrteil, SirWoezel (who hid their comment due to spoiler) and Alexander.

on 1. November 2020, 00:33 by Alexander Rappa
Loved this! Fun from start to finish

on 30. October 2020, 20:56 by LongOrteil
Spectacular puzzle. Great job!

on 30. October 2020, 18:17 by glum_hippo
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Difficulty:4
Rating:94 %
Solved:23 times
Observed:8 times
ID:0004M6

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