Logic Masters Deutschland e.V.

Even The Odd Killer

(Published on 29. August 2020, 13:48 by tzael)

Normal Sudoku rules apply. Killer cage rules apply. Digits inside a cage must sum to the total and does not repeat.

In addition, some cages are marked.
Cages marked with e, contain only even digits.
Cages marked with o, contain only odd digits.
All cages marked with e or o, have unique combinations of digits.

Finally, a white circle indicates the smallest digit inside that cage.

Penpa+ link

Solution code: Row 8, 9

Last changed on on 29. August 2020, 21:30

Solved by Realshaggy, Quarterthru, udukos, Narayana, niaji, Jesper, Snowhare, Julianl, NikolaZ, Rollo, puzzlemuncher69, skywalker, misko, zorant, SudokuExplorer, rimodech, djorr
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Comments

on 11. December 2020, 00:32 by SudokuExplorer
A lovely parity sudoku, thanks :-)

on 30. August 2020, 19:34 by Quarterthru
ONLY the e / o cages must have different digits. Numbered cages do not follow this restriction nor do they restrict the e/o cages.

on 30. August 2020, 18:39 by Narayana
@geronimo92:
Take a look at my comment below yours specially the part that says for future solvers. I think that will clarify the rule. The puzzle IS interesting. Take a second look. :)

on 30. August 2020, 17:44 by geronimo92
Sorry but i understood the rule correctly (only cages marked with e or o ) but i still remain with contradictions again and again.... no matter what, let's give up and look forward for another more interesting one....

on 30. August 2020, 08:15 by Narayana
Once you understand what you have to do the puzzle is nice and easy but the most powerful rule is poorly explained. Which resulted in 2 full restarts, plenty of contradictions and me shouting at the screen when I finally figured it out.

________________

For future solvers:

When they say “All cages marked with e or o, have unique combinations of digits.”

That means if a MARKED cage contains for example the digits {ABC} there can NOT exist another cage of the same size containing the exact same set of digits. Here order does not matter the set {B A C} is still the same as the set {ABC} thus {BAC} is not allowed in another cage. However {ABD} IS allowed.
If you heavily use the power of this rule you should encounter a smooth solve.

________________

For people curious about what I did that gave me such a head ache: I interpreted unique combination as referring to the “pencil marks”
For example the 8 cage is not marked so it can have several combinations for pencil marks like 1+7 or 3+5 but the e cages in column 4 are both marked
So the must give numbers that can only made in one way with even numbers
So out of the combinations:
2 + 4 = 6
2 + 6 = 8
2 + 8 = 10
4 + 6 = 10
4 + 8 = 12
6 + 8 = 14
The cage value 10 is forbidden since it results from two different pencil marks… Clearly this was not the intent of the problem but some how it made sense to me :(

Difficulty:4
Rating:85 %
Solved:17 times
Observed:9 times
ID:000482

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