Octo Nr. 4

(Published on 27. July 2020, 18:09 by DocLogic)

In every row (A - H) and in every column (1 - 8) are the figures from 1 - 8 once each.

Equations:

B7 + B8 = 11

E3 + F3 + G3 = 8

C5 - D5 = 4

D8 - E8 - F8 = 4

B3 * B4 = 4

D6 * E6 * F6 = 48

G1 : H1 = 2

H7 : H8 = 3

Additional conditions:

A7=G4

A8=C4

A1 = E7 = H5

B2+H2=F3

B6-H3=F7

A5 ≠ F1

C1<3 oder F6>5

Solution code: the two long diagonals: from upper left to bottom right, and from upper right to bottom left

Solved by ManuH, Amedoru, Zzzyxas, Nothere, NikolaZ, SKORP17, marcmees, zhergan, skywalker, AnnaTh, saskia-daniela, zorant, celisa, rimodech, geronimo92, ildiko, ch1983, Ragna, Rollo, moss, Teck, Tojvoh, bob, derwolf23, drolli38, hra2065, Nensche777, Laje6, zuzanina, Katchoo, cornuto, janedoe, flaemmchen, Joo M.Y, Dotty, Nr.2, ffricke, misko, myothername, lutzreimer, Hippologicus

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