Octo Nr. 4
(Published on 27. July 2020, 18:09 by DocLogic)
Equations:
B7 + B8 = 11
E3 + F3 + G3 = 8
C5 - D5 = 4
D8 - E8 - F8 = 4
B3 * B4 = 4
D6 * E6 * F6 = 48
G1 : H1 = 2
H7 : H8 = 3
Additional conditions:
A7=G4
A8=C4
A1 = E7 = H5
B2+H2=F3
B6-H3=F7
A5 ≠ F1
C1<3 oder F6>5
Solution code: the two long diagonals: from upper left to bottom right, and from upper right to bottom left
Solved by ManuH, Amedoru, Zzzyxas, Nothere, NikolaZ, SKORP17, marcmees, zhergan, skywalker, AnnaTh, saskia-daniela, zorant, celisa, rimodech, geronimo92, ildiko, ch1983, Ragna, Rollo, moss, Teck, Tojvoh, bob, derwolf23, drolli38, hra2065, Nensche777, Laje6, zuzanina, Katchoo, cornuto, janedoe, flaemmchen, Joo M.Y, Dotty, Nr.2, ffricke, misko, myothername, lutzreimer, Hippologicus
Comments
on 17. August 2020, 16:11 by Tojvoh
Sehr schön! Danke für das schöne Rätsel
