Octo Nr. 3
(Published on 2. April 2020, 22:39 by DocLogic)
Equations:
A7 + B7 = 13
E3 + E4 + E5 = 19
B5 - C5 = 4
H5 - H6 - H7 = 1
D8 * E8 = 32
F7 * G7 * H7 = 28
B1 : B2 = 2
G3 : H3 = 4
Additional conditions:
B3 = F5
B7 = D5
E7 = H1
A1 = D4 = G8
A5 + H4 > 10
A5 + H8 = F1
F2 < C2 < C1
A3 + F4 = A6 * F3
Solution code: the two long diagonals: from upper left to bottom right, and from upper right to bottom left
Last changed on on 3. April 2020, 00:28
Solved by Julianl, sf2l, zhergan, Nylimb, saskia-daniela, ManuH, skywalker, ch1983, Zzzyxas, marcmees, NikolaZ, Statistica, Alex, rimodech, Nothere, Joe Average, flaemmchen, Player, zorant, Uhu, moss, Rollo, ... SKORP17, zuzanina, ildiko, pin7guin, Richard, ffricke, AnnaTh, hra2065, Dotty, drolli38, Laje6, misko, Katchoo, cornuto, janedoe, Joo M.Y, Nr.2, myothername, Hippologicus, KerstAn, Lili Lavender
Comments
on 5. May 2024, 21:00 by Lili Lavender
Wunderbares Rätsel, hat Spass gemacht, DANKE :-)
on 3. April 2020, 01:42 by zhergan
Thanks for nice puzzle..
on 3. April 2020, 01:42 by sf2l
never mind, thank you for your puzzles anyway
on 3. April 2020, 00:28 by DocLogic
HTML mistake corrected
