Double Dutch Sudoku Advent (1) - Search Nine vs. Rossini
(Published on 1. December 2014, 12:00 by Richard)
Two years ago, Arvid and I have created a sudoku advent calender with sudoku variants that were (relatively) unknown in the puzzle portal back then. This year we have created another advent calender, which has a different theme: every sudoku contains a combination of two different variants. We have chosen 12 well known variants and 12 relatively unknown variants: every day we combine two of these in the schedule AB BC CD … KL LA. While we were creating and test-solving these combination puzzles we both learned a lot. We strongly believe that combining two variants leads to interesting and surprising new solving techniques which really adds to the solving fun. We hope players will enjoy and learn as much as we did.
Logically solvable
All puzzles can be solved completely logically although the logic is sometimes well hidden and is inherent to the combination of restrictions that the different types offer. For that reason we have written some solving hints for most of the puzzles, published in a very tiny font. If you want to read the hints, simply copy these in a text editor and enlarge the font size.
Search Nine
Place the digits from 1 tot 9 in every row, column and 3x3-block. Every arrow is pointing at number 9 in the respective row or column. The number in the arrow is the distance (with respect to the number of cells) from the arrow to the 9.
Rossini
The arrows outside the grid indicate that the first three digits are in ascending or descending order (the highest digit is at the sharp end of the arrow). If there is no arrow outside the first three digits cannot be in either ascending or descending order.
Solving hints
This first puzzle is not so hard yet; an easy one to get started.
9 in R2 in R2C46; R2C37 = pair {13}
R3C2 not 1 because of Rossini-arrows. R3C3 not 9. :=> R3C7 = 9; R3C8 = 1; R2C7 = 3; R2C3 = 1; R2C4 = 9; R1C4 = 1; R3C2 and R8C7 = 5
9 in 3x3-block bottom right must go in R7C9; R7C2 = 7
9 in C8 not in R6C8 or R4C8 (Rossini); R5C8 = 9; R7C8 = 2; R7C7 = 1
1 in block bottom left must be in R8C1; 9 in block bottom left in R9C1; R9C6 = 5; R6C1 = 3
1 in block middle left must be in R5C2; R6C9 = 1
R7C6 = 8; R8C6 = 6 or 7; 8 in block bottom left in R9C2; R8C5 = 9
Arrow in R8C3 can’t be 2 (Rossini), 3 or 6, so must be 4. R4C3 = 9; R4C9 = 6; R4C8 = 7; R4C7 = 8
R8C2 + R9C3 = pair {23}
Solution code: Row 5, followed by column 5.
Comments
on 28. March 2022, 12:07 by Nick Smirnov
Penpa:
https://tinyurl.com/2on9zdon
on 2. December 2014, 20:55 by Richard
I agree with you berni. This is the standard notation for this type. I found it confusing too, but didn't want to change from the standard notation.
on 2. December 2014, 20:37 by berni
Hab' erst mal die verwirrenden Randsymbole alle umgedreht. Danach wurde es deutlich einfacher.
on 1. December 2014, 15:36 by flaemmchen
Freue mich auf die nächsten Adventskalender-Türchen :-))
on 1. December 2014, 14:50 by zorant
Great!!!!
on 1. December 2014, 14:35 by Goodie
Super Idee! Bin gespannt auf morgen!
on 1. December 2014, 14:32 by SilBer
Das hat richtig Spaß gemacht!! "Obwohl" es Sudokus sind. ;) Aber die Search-Nine-Variante ist auch einfach eine schöne. Jetzt bin ich sehr gespannt, wie es weitergeht...
on 1. December 2014, 13:53 by r45
Hört sich und fühlt sich bereits prima an. Vielen Dank vorab an Euch beide. Ein toller Start in die Adventszeit.
on 1. December 2014, 12:26 by Eisbär
We were a bit confused in the beginning also :-D
If an arrow for example is pointing to the right ( >> ) the correct order is 1, 2, 3...
on 1. December 2014, 12:22 by fridgrer
if the first digits in a row would be 1,2,3 would there be a sign >> on the left side? (i read the puzzle like that, but that would be contrary to the usual meaning of the sign >>, that’s why i am a bit confused; sorry)
