Spiral City Construction (II)
(Published on 26. July 2013, 12:00 by Richard)
Place all buildings in the grid. Buildings may be rotated and mirrored. They may not touch each other, not even diagonally. All unused cells form a single, closed loop. The given grid is a spiral. Building segments are numbered from 1 to 30, starting from the entrance of the spiral (top left) and moving towards the center. The numbers outside the grid represent the sum of the building segments in the corresponding row or column.
Solution code: The number of knicks in the loop; row by row, top to bottom. (Example: 40228244)
Last changed on on 26. July 2013, 12:34
Solved by sloffie, r45, Babsi, AnnaTh, Zzzyxas, deu, pirx, moss, RobertBe, saskia-daniela, Alex, lutzreimer, zorant, Hansjo, jirk, pin7guin, RALehrer, ildiko, mango, ibag, Mathi, sandmoppe, Mody, ManuH, lupo, ... Faxi, MagicMichi, marcmees, Katrin K, KlausRG, Matt, Uhu, Nothere, adam001, skywalker, misko, EKBM, RockyRoer, polar, Realshaggy, Nick Smirnov, AstralSky, helle, Krokant, Madoka42, Echatsum
Comments
on 1. April 2022, 23:47 by Nick Smirnov
Penpa:
https://tinyurl.com/ya49b48w
Use 'Tab' button to switch between Surface, Line and Number modes.
on 2. January 2014, 19:33 by Eisbär
What a beauty... :-)))
on 29. July 2013, 18:53 by AndreasS
vielen Dank für das tolle Rãtsel. Am Anfang dachte ich "Wie soll das den gehen". super Konstruktion.
on 26. July 2013, 18:57 by Alex
that was good fun! Thank you!
on 26. July 2013, 13:52 by AnnaTh
Gerne mehr!
on 26. July 2013, 13:09 by r45
Schöööö...n!
Last changed on 26. July 2013, 12:35
on 26. July 2013, 12:34 by Richard
Fine-tuning of instructions:
buildings may also be mirrored.
