June Pentomino Month (4) - Increasing Pentomino Sudoku
(Published on 28. June 2013, 12:00 by Richard)
In all of the 8 3x3-boxes on the edge of the grid a pentomino has to be placed in the way they are presented: the pentominos must not be rotated, mirrored or moved within the 3x3-box. The sum of the digits covered by a pentomino shape is increasing with 2; If the sum of the F pentomino is 15, P=17, T=19 and so on. If F=16, P=18, T=20…
The pentominos have to be placed clockwise in increasing order. Finding out where to place the pentominos is part of the puzzle.
Solve online in Penpa+ (thx Nick Smirnov!)
Solution code: Row 4, followed by row 6.
Comments
on 9. October 2022, 07:59 by Richard
Added link and tag for online solving. Thx Nick!
on 2. October 2022, 23:46 by Nick Smirnov
Penpa:
https://tinyurl.com/2n4pf7fl
on 28. June 2013, 21:19 by Rollo
Klasse Idee!
on 28. June 2013, 19:37 by ManuH
Danke!
on 28. June 2013, 19:15 by ibag
F hat die niedrigste, dann P, dann T usw., Z die höchste.
on 28. June 2013, 19:07 by ManuH
Hat F auf jeden Fall die niedrigste Summe? Oder ist das nur zufällig in beiden Beispielen oben so?
