Springinsfeld 5x5
(Published on 10. April 2013, 12:00 by adam001)
Someone has jumped 25 times to form a loop from cell to cell. He has visited each cell once and left each time the amount of cells he jumps horizontally and vertically (but not necessary in this order) to land in the next.
Can you trace his path?
Can you trace his path?
Solution code: Put in the upper left cell an A, in the next visited cell a B, and so forth (till Y). The solution code: the 5 letters on the 4th row.
Last changed on on 10. April 2013, 12:44
Solved by Rollo, pokerke, pirx, pin7guin, MiR, BFaw, ch1983, StefanSch, Zzzyxas, CHalb, RALehrer, Ute2, saskia-daniela, dm_litv, Luigi, ibag, HaSe, ildiko, joyal, jirk, mango, derwolf23, pwahs, rimodech, Alex, ... wolx, Carolin, tuace, uvo, Senor Dingdong, rob, Joe Average, kaberg, sf2l, jessica6, Danielle, Nothere, zuzanina, Krokant, Joo M.Y, amitsowani, skywalker, jplank, Raistlen, Dugong, jogerth, Onyx
Comments
Last changed on 4. June 2017, 23:13
on 4. June 2017, 22:40 by jessica6
Wie sind denn die Angaben zu verstehen? Eine Zahl waagrecht und die andere senkrecht? Oder ist immer nur eine der beiden Zahlen richtig?
Edit: Ist anscheinend eine kombinierte Bewegung. Also 1/2 = Sprung um (+-1, +-2) oder (+-2, +-1)
on 14. November 2014, 02:25 by Senor Dingdong
Quite hard and interesting. Nice new puzzle type!
