Januar Pentomino-Monat (2): Pentominofänger
(Published on 13. January 2012, 12:00 by Richard)
January Pentomino month (2) - Pentomino in the box
Place the 12 pentominos in the grid, so that they don't touch each other, not even diagonally. The pentominos may be rotated and/or mirrored. Every boldly outlined area contains exactly three cells that belong to
two or three different pentominos.
Solve online in Penpa+ (thx Nick Smirnov!)
Solution code: Row 1, followed by column 11. For every cell the letter of the pentomino and '-' for an empty cell.
Last changed on on 15. October 2022, 06:26
Solved by Alex, Laje6, Luigi, Zzzyxas, pin7guin, pokerke, lupo, ManuH, zuzanina, mathezwerg, ch1983, saskia-daniela, Toastbrot, sandmoppe, Mody, rob, BFaw, ibag, joyal, relzzup, martin1456, Hansjo, Rollo, ... Faxi, flaemmchen, Joe Average, brecher92, muhorka, Joo M.Y, EKBM, johnreid, sf2l, tuace, Matt, Uhu, marcmees, cdwg2000, amitsowani, misko, dandbdi, Realshaggy, Nick Smirnov, Mark Sweep, Echatsum
Comments
on 15. October 2022, 06:26 by Richard
Added link and tag for online solving. Thx Nick!
on 8. September 2022, 02:42 by Nick Smirnov
Penpa:
https://tinyurl.com/2g368rwz
on 13. January 2012, 15:19 by pin7guin
Klasse! Das hat richtig viel Spaß gemacht. Danke, Richard!
on 13. January 2012, 13:47 by Alex
that was a lot of fun, great construction!