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CrocoPuzzle Adventskalender 2011: Tag 23 (Tapaeske Dreiecke IV)

(Published on 23. December 2011, 08:00 by berni)


This puzzle is part of the

CrocoPuzzle Adventskalender 2011


Instructions: In your mind divide every cell along the two diagonals. Now blacken two of the resulting triangles that share an edge. The numbers in the circles give the number of blackend triangles around: Every number gives a group of connected black triangles. Groups are separated by at least one white triangle. The position and the order of the numbers in the circle does not matter.

ExampleSolution

Solution code: The fourth row. Use the letters Q (top left), W (top right), A (bottom left), S (bottom right) to give the position of the blackend (large) triangle. In the example the first row would be WAW.

Last changed on on 12. February 2013, 13:26

Solved by volker, Luigi, alberto, dm_litv, MiR, Jun, PRW, Mathi, CHalb, yusaku, certik, Toastbrot, pokerke, RobertBe, ManuH, rob, ch1983, Rollo, hopppe, Calavera, Alex, garganega, joyal, Hansjo, David McNeill, ... adam001, ildiko, sojaboon, marsigel, relzzup, jimrity, Joo M.Y, matter, Joe Average, moss, tuace, Fiffi, Uhu, pandiani42, jessica6, bob, Carolin, pirx, Matt, EKBM, misko, puzzler05, DiMono, Echatsum
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Comments

on 12. February 2013, 13:26 by berni
Stichwort hinzugefügt

on 13. February 2012, 17:47 by pin7guin
Warum ich zwei Adventskalenderrätsel "übersehen" habe, weiß ich auch nicht. Jetzt kann jedenfalls Weihnachten kommen... ;-)
Danke, Berni, für diese tolle Adventsüberraschung!

on 29. December 2011, 00:43 by ibag
An dieser Stelle auch von mir vielen Dank für den tollen Kalender mit den kreativen neuen Rätseln!

Difficulty:3
Rating:86 %
Solved:94 times
Observed:7 times
ID:00017Y

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