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CrocoPuzzle Adventskalender 2011: Tag 9 (Tapaeske Dreiecke III)

(Published on 9. December 2011, 08:00 by berni)


This puzzle is part of the

CrocoPuzzle Adventskalender 2011


Instructions: In your mind divide every cell along the two diagonals. Now blacken two of the resulting triangles that share an edge. The numbers in the circles give the number of blackend triangles around: Every number gives a group of connected black triangles. Groups are separated by at least one white triangle. The position and the order of the numbers in the circle does not matter.

ExampleSolution

Solution code: The eigth row. Use the letters Q (top left), W (top right), A (bottom left), S (bottom right) to give the position of the blackend (large) triangle. In the example the first row would be WAW.

Last changed on on 12. February 2013, 13:23

Solved by ch1983, rimodech, pokerke, Skydiver80, garganega, Luigi, Jun, Laje6, MaSa, ManuH, uvo, BFaw, yusaku, Rollo, Katrin K, flaemmchen, ffricke, FreshMeat, alberto, Alex, Antarez, ibag, Statistica, hopppe, ... marsigel, ildiko, sf2l, adam001, sojaboon, relzzup, jimrity, Joo M.Y, Joe Average, matter, tuace, Uhu, pandiani42, Matt, jessica6, bob, Carolin, pirx, athin, EKBM, misko, puzzler05, DiMono, Echatsum
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Comments

on 12. February 2013, 13:23 by berni
Stichwort hinzugefügt

Last changed on 9. December 2011, 12:51

on 9. December 2011, 12:50 by flaemmchen
Diese Dreiecks-Geschichten gefallen mir ausserordentlich gut! Hoffentlich kommen noch ein paar davon im Adventskalender :))
... allerdings kann ich mir die Diagonalen nicht nur denken, ich muss sie schon "richtig" einzeichnen ;-)

Difficulty:3
Rating:85 %
Solved:112 times
Observed:4 times
ID:00017K

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